Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
linear circuitV1​ = 9 VV2​ = 24 VIRL​

A linear resistive circuit contains two independent voltage sources, V1 = 9 V and V2 = 24 V. With both sources on, the current through the load resistor is I = 16.5 mA. With V2 switched off (replaced by a short circuit) and V1 unchanged, the load current is 9.5 mA. Find the load current I when V1 is switched off and only V2 = 24 V is active.

I = 16.5 mA (both sources)I = 9.5 mA (only V1)
I = mA
2.Easy
R1​ = 4 ΩIR1​R2​ = 8 Ω+−V1​15 VR3​6 ΩA+−V2​15 V

Use superposition to find the current IR1 through R1 in the direction of the arrow.

V1 = 15 VV2 = 15 VR1 = 4 ΩR2 = 8 ΩR3 = 6 Ω
IR1 = A
3.Medium
R1​ = 2 ΩR3​ = 5 Ω+−V1​30 VR2​4 ΩAR4​3 ΩIR4​BIs​1.5 A

Use superposition to find the power PR4 absorbed by R4.

V1 = 30 VIs = 1.5 AR1 = 2 ΩR2 = 4 ΩR3 = 5 ΩR4 = 3 Ω
PR4 = W
4.Medium
linear circuitVs​Is​IRL​

A linear resistive circuit contains one voltage source Vs and one current source Is. The current I through a load resistor is measured twice: with Vs = 5 V and Is = 2 mA, I = 1.75 mA; with Vs = 15 V and Is = 1 mA, I = 4 mA. Find the load current I when Vs = 10 V and Is = 1 mA.

5 V, 2 mA → 1.75 mA15 V, 1 mA → 4 mAVs = 10 V, Is = 1 mA
I = mA
5.Hard
R1​ = 30 ΩR2​ = 20 ΩR4​ = 25 Ω+−V1​24 VR3​10 ΩIR3​AIs​2 AB+−V2​?

Find the value of the voltage source V2 (polarity as shown) that makes the current IR3 through R3 equal to zero.

V1 = 24 VIs = 2 AR1 = 30 ΩR2 = 20 ΩR3 = 10 ΩR4 = 25 Ω
V2 = V
6.Hard
R1​ = 20 ΩR2​ = 3 ΩIR2​R4​ = 20 Ω+−V1​12 VR3​25 ΩAIs​3 AB+−V2​36 V

Use superposition to find the current IR2 through R2 in the direction of the arrow.

V1 = 12 VIs = 3 AV2 = 36 VR1 = 20 ΩR2 = 3 ΩR3 = 25 ΩR4 = 20 Ω
IR2 = A

Answer key

  1. 1. I = 7 mA
  2. 2. IR1 = 1.154 A
  3. 3. PR4 = 3.797 W
  4. 4. I = 2.75 mA
  5. 5. V2 = 14 V
  6. 6. IR2 = −2.619 A

Full step-by-step solutions: practise this topic on examproblems.com.