Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the contribution V_R3′ of V₁ alone to the voltage V_R3 across R₃ with the polarity shown.

V₁ = 10 VV₂ = 24 VR₁ = 12 ΩR₂ = 10 ΩR₃ = 6 Ω

V_R3′ = V

2.Easy

Use superposition to find the current I_R2 through R₂ in the direction of the arrow.

V₁ = 10 VV₂ = 10 VR₁ = 2 ΩR₂ = 12 ΩR₃ = 6 Ω

I_R2 = A

3.Medium

Use superposition to find the voltage V_R2 across R₂ with the polarity shown.

V₁ = 6 VI_s = 2.5 AR₁ = 4 ΩR₂ = 6 ΩR₃ = 3 ΩR₄ = 2 Ω

V_R2 = V

4.Medium

A linear resistive circuit contains one voltage source V_s and one current source I_s. The current I through a load resistor is measured twice: with V_s = 6 V and I_s = 4 mA, I = 2.4 mA; with V_s = 15 V and I_s = 2 mA, I = 10.8 mA. Find the load current I when V_s = 12 V and I_s = 5 mA.

6 V, 4 mA → 2.4 mA15 V, 2 mA → 10.8 mAV_s = 12 V, I_s = 5 mA

I = mA

5.Hard

Use superposition to find the current I_R3 through R₃ in the direction of the arrow.

V₁ = 6 VI_s = 3 AV₂ = 18 VR₁ = 4 ΩR₂ = 5 ΩR₃ = 10 ΩR₄ = 10 Ω

I_R3 = A

6.Hard

Use superposition to find the current I_R4 through R₄ in the direction of the arrow.

V₁ = 9 VI_s = 1.5 AV₂ = 36 VR₁ = 12 ΩR₂ = 4 ΩR₃ = 20 ΩR₄ = 2 Ω

I_R4 = A

Answer key

1. V_R3′ = 2.381 V
2. I_R2 = −0.1852 A
3. V_R2 = 4.054 V
4. I = 6.6 mA
5. I_R3 = 1.128 A
6. I_R4 = −0.9722 A

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