Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
R1​ = 3 ΩR2​ = 5 Ω+−V1​18 VR3​6 Ω+−VR3​A+−V2​6 V

Use superposition to find the contribution VR3′ of V1 alone to the voltage VR3 across R3 with the polarity shown.

V1 = 18 VV2 = 6 VR1 = 3 ΩR2 = 5 ΩR3 = 6 Ω
VR3′ = V
2.Easy
R1​ = 8 Ω+−V1​10 VR2​10 ΩIR2​AIs​3 A

Use superposition to find the current IR2 through R2 in the direction of the arrow.

V1 = 10 VIs = 3 AR1 = 8 ΩR2 = 10 Ω
IR2 = A
3.Medium
linear circuitVs​Is​IRL​

A linear resistive circuit contains one voltage source Vs and one current source Is. The current I through a load resistor is measured twice: with Vs = 15 V and Is = 2 mA, I = 8.5 mA; with Vs = 5 V and Is = 6 mA, I = 5.5 mA. Find the load current I when Vs = 8 V and Is = 10 mA.

15 V, 2 mA → 8.5 mA5 V, 6 mA → 5.5 mAVs = 8 V, Is = 10 mA
I = mA
4.Medium
linear circuitVs​Is​IRL​

A linear resistive circuit contains one voltage source Vs and one current source Is. The current I through a load resistor is measured twice: with Vs = 20 V and Is = 2 mA, I = 8.2 mA; with Vs = 10 V and Is = 5 mA, I = 4.5 mA. Find the load current I when Vs = 12 V and Is = 8 mA.

20 V, 2 mA → 8.2 mA10 V, 5 mA → 4.5 mAVs = 12 V, Is = 8 mA
I = mA
5.Hard
linear circuitV1​V2​Is​IRL​

A linear resistive circuit contains three independent sources: V1, V2 and Is. The current I through a load is measured three times. With all sources at their normal values, I = 13 mA. With V1 doubled and the other two unchanged, I = 19 mA. With the direction of Is reversed and the other two unchanged, I = 6 mA. Find the load current I when V2 is switched off and V1 and Is have their normal values.

normal: I = 13 mA2·V1: I = 19 mA−Is: I = 6 mA
I = mA
6.Hard
linear circuitV1​V2​Is​IRL​

A linear resistive circuit contains three independent sources: V1, V2 and Is. The current I through a load is measured three times. With all sources at their normal values, I = −26 mA. With V1 doubled and the other two unchanged, I = −35.5 mA. With the direction of Is reversed and the other two unchanged, I = −17 mA. Find the load current I when V2 is switched off and V1 and Is have their normal values.

normal: I = −26 mA2·V1: I = −35.5 mA−Is: I = −17 mA
I = mA

Answer key

  1. 1. VR3′ = 8.571 V
  2. 2. IR2 = 1.889 A
  3. 3. I = 9 mA
  4. 4. I = 5.6 mA
  5. 5. I = 9.5 mA
  6. 6. I = −14 mA

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