A linear resistive circuit contains two independent voltage sources, V1 = 15 V and V2 = 12 V. With both sources on, the current through the load resistor is I = 23 mA. With V2 switched off (replaced by a short circuit) and V1 unchanged, the load current is 7 mA. Find the load current I when V1 is switched off and only V2 = 12 V is active.
Superposition worksheet with answers
A linear resistive circuit contains two independent voltage sources, V1 = 5 V and V2 = 12 V. With both sources on, the current through the load resistor is I = −7 mA. With V2 switched off (replaced by a short circuit) and V1 unchanged, the load current is −16 mA. Find the load current I when V1 is raised to 10 V and V2 stays at 12 V.
A linear resistive circuit contains one voltage source Vs and one current source Is. The current I through a load resistor is measured twice: with Vs = 5 V and Is = 6 mA, I = 1.85 mA; with Vs = 8 V and Is = 3 mA, I = 2.3 mA. Find the load current I when Vs = 10 V and Is = 6 mA.
Use superposition to find the current IR1 through R1 in the direction of the arrow.
Find the value of the voltage source V2 (polarity as shown) that makes the current IR3 through R3 equal to zero.
Use superposition to find the power PR1 absorbed by R1.
Answer key
- 1. I = 16 mA
- 2. I = −23 mA
- 3. I = 3.1 mA
- 4. IR1 = 1.943 A
- 5. V2 = 24 V
- 6. PR1 = 3.828 W
Full step-by-step solutions: practise this topic on examproblems.com.