Use superposition to find the contribution IR2″ of V2 alone to the current IR2 through R2 in the direction of the arrow.
Superposition worksheet with answers
1.Easy
V1 = 18 VV2 = 10 VR1 = 8 ΩR2 = 3 ΩR3 = 5 Ω
IR2″ = A
2.Easy
Use superposition to find the current IR1 through R1 in the direction of the arrow.
V1 = 8 VV2 = 12 VR1 = 2 ΩR2 = 8 ΩR3 = 6 Ω
IR1 = A
3.Medium
Use superposition to find the current IR2 through R2 in the direction of the arrow.
V1 = 12 VIs = 3 AR1 = 4 ΩR2 = 12 ΩR3 = 2 ΩR4 = 8 Ω
IR2 = A
4.Medium
Use superposition to find the power PR2 absorbed by R2.
V1 = 24 VIs = 3 AR1 = 2 ΩR2 = 12 ΩR3 = 4 ΩR4 = 3 Ω
PR2 = W
5.Hard
Use superposition to find the power PR1 absorbed by R1.
V1 = 12 VIs = 4 AV2 = 9 VR1 = 20 ΩR2 = 12 ΩR3 = 10 ΩR4 = 12 Ω
PR1 = W
6.Hard
Use superposition to find the voltage VR2 across R2 with the polarity shown.
V1 = 15 VIs = 2 AV2 = 9 VR1 = 5 ΩR2 = 25 ΩR3 = 15 ΩR4 = 5 Ω
VR2 = V
Answer key
- 1. IR2″ = −1.646 A
- 2. IR1 = 0.5263 A
- 3. IR2 = −1.038 A
- 4. PR2 = 18.14 W
- 5. PR1 = 0.6201 W
- 6. VR2 = −5.741 V
Full step-by-step solutions: practise this topic on examproblems.com.