Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
R1​ = 4 Ω+−V1​24 VR2​10 ΩIR2​AIs​1 A

Use superposition to find the current IR2 through R2 in the direction of the arrow.

V1 = 24 VIs = 1 AR1 = 4 ΩR2 = 10 Ω
IR2 = A
2.Easy
R1​ = 2 ΩR2​ = 2 Ω+−V1​8 VR3​6 Ω+−VR3​A+−V2​6 V

Use superposition to find the contribution VR3″ of V2 alone to the voltage VR3 across R3 with the polarity shown.

V1 = 8 VV2 = 6 VR1 = 2 ΩR2 = 2 ΩR3 = 6 Ω
VR3″ = V
3.Medium
linear circuitVs​Is​IRL​

A linear resistive circuit contains one voltage source Vs and one current source Is. The current I through a load resistor is measured twice: with Vs = 15 V and Is = 10 mA, I = 37.5 mA; with Vs = 15 V and Is = 2 mA, I = 31.5 mA. Find the load current I when Vs = 12 V and Is = 2 mA.

15 V, 10 mA → 37.5 mA15 V, 2 mA → 31.5 mAVs = 12 V, Is = 2 mA
I = mA
4.Medium
R1​ = 12 ΩIR1​R3​ = 3 Ω+−V1​18 VR2​4 ΩAR4​6 ΩBIs​2.5 A

Use superposition to find the current IR1 through R1 in the direction of the arrow.

V1 = 18 VIs = 2.5 AR1 = 12 ΩR2 = 4 ΩR3 = 3 ΩR4 = 6 Ω
IR1 = A
5.Hard
R1​ = 6 ΩR2​ = 6 Ω+−VR2​R4​ = 4 Ω+−V1​10 VR3​15 ΩAIs​2 AB+−V2​9 V

Use superposition to find the voltage VR2 across R2 with the polarity shown.

V1 = 10 VIs = 2 AV2 = 9 VR1 = 6 ΩR2 = 6 ΩR3 = 15 ΩR4 = 4 Ω
VR2 = V
6.Hard
R1​ = 5 ΩR2​ = 20 ΩIR2​R4​ = 12 Ω+−V1​24 VR3​25 ΩAIs​3 AB−+V2​15 V

Use superposition to find the power PR2 absorbed by R2.

V1 = 24 VIs = 3 AV2 = 15 VR1 = 5 ΩR2 = 20 ΩR3 = 25 ΩR4 = 12 Ω
PR2 = W

Answer key

  1. 1. IR2 = 2 A
  2. 2. VR3″ = 2.571 V
  3. 3. I = 25.5 mA
  4. 4. IR1 = 0.9063 A
  5. 5. VR2 = 2.58 V
  6. 6. PR2 = 77.08 W

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