Use superposition to find the contribution IR3″ of V2 alone to the current IR3 through R3 in the direction of the arrow.
Superposition worksheet with answers
1.Easy
V1 = 20 VV2 = 20 VR1 = 3 ΩR2 = 4 ΩR3 = 2 Ω
IR3″ = A
2.Easy
Use superposition to find the current IR3 through R3 in the direction of the arrow.
V1 = 18 VV2 = 6 VR1 = 2 ΩR2 = 2 ΩR3 = 2 Ω
IR3 = A
3.Medium
Find the value of the current source Is (direction as shown) that makes the current IR3 through R3 equal to zero.
V1 = 6 VR1 = 15 ΩR2 = 8 ΩR3 = 12 ΩR4 = 8 Ω
Is = A
4.Medium
Use superposition to find the voltage VR2 across R2 with the polarity shown.
V1 = 15 VIs = 4 AR1 = 20 ΩR2 = 10 ΩR3 = 8 ΩR4 = 5 Ω
VR2 = V
5.Hard
Use superposition to find the current IR2 through R2 in the direction of the arrow.
V1 = 24 VIs = 3 AV2 = 36 VR1 = 25 ΩR2 = 2 ΩR3 = 8 ΩR4 = 6 Ω
IR2 = A
6.Hard
Use superposition to find the power PR2 absorbed by R2.
V1 = 18 VIs = 0.5 AV2 = 12 VR1 = 4 ΩR2 = 8 ΩR3 = 4 ΩR4 = 10 Ω
PR2 = W
Answer key
- 1. IR3″ = 2.308 A
- 2. IR3 = 4 A
- 3. Is = 0.2609 A
- 4. VR2 = −3.475 V
- 5. IR2 = 1.694 A
- 6. PR2 = 1.28 W
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