Three-phase power worksheet with answers

Free printable Three-phase power worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
ABCVL​ = 400 VZ = 18 + j24 Ωper phase

A balanced Δ-connected load has an impedance of 18 + j24 Ω per phase. It is supplied from a balanced three-phase source with a line-to-line voltage of 400 V. Find the magnitude of the phase current Iph flowing through each impedance.

VL = 400 VZ = 18 + j24 Ω per phase
Iph = A
2.Easy
ABCVL​ = 600 VIL​ = ?NZ = 7 + j24 Ωper phase

A balanced Y-connected load has an impedance of 7 + j24 Ω per phase. It is supplied from a balanced three-phase source with a line-to-line voltage of 600 V. Find the magnitude of the line current IL.

VL = 600 VZ = 7 + j24 Ω per phase
IL = A
3.Medium
ABCVL​ = 415 VIL​ = ?M110 kW, η = 92%cos φ = 0.82

A three-phase induction motor delivers 110 kW of mechanical output power at full load. At this load its efficiency is 92% and its power factor is 0.82 lagging. The supply has a line-to-line voltage of 415 V. Find the line current IL.

Pout = 110 kWη = 92%cos φ = 0.82VL = 415 V
IL = A
4.Medium
ABCVL​ = 690 VIL​ = ?M75 kW, η = 93%cos φ = 0.85

A three-phase induction motor delivers 75 kW of mechanical output power at full load. At this load its efficiency is 93% and its power factor is 0.85 lagging. The supply has a line-to-line voltage of 690 V. Find the line current IL.

Pout = 75 kWη = 93%cos φ = 0.85VL = 690 V
IL = A
5.Hard
P = 150 kWφ1​S1​Q2​QC​

A balanced three-phase load takes 150 kW at a power factor of 0.75 lagging from a 415 V (line-to-line), 60 Hz supply. A three-phase capacitor bank in parallel with the load must raise the overall power factor to 0.95 lagging. The real power stays the same. The capacitors are connected in Y. Find the capacitance Cph of each capacitor in µF.

P = 150 kWpf1 = 0.75pf2 = 0.95VL = 415 Vf = 60 Hz
Cph = µF
6.Hard
P = 100 kWφ1​S1​Q2​QC​

A balanced three-phase load takes 100 kW at a power factor of 0.72 lagging from a 480 V (line-to-line), 60 Hz supply. A three-phase capacitor bank in parallel with the load must raise the overall power factor to 0.98 lagging. The real power stays the same. The capacitors are connected in Y. Find the capacitance Cph of each capacitor in µF.

P = 100 kWpf1 = 0.72pf2 = 0.98VL = 480 Vf = 60 Hz
Cph = µF

Answer key

  1. 1. Iph = 13.33 A
  2. 2. IL = 13.86 A
  3. 3. IL = 202.9 A
  4. 4. IL = 79.39 A
  5. 5. Cph = 1278 µF
  6. 6. Cph = 875.9 µF

Full step-by-step solutions: practise this topic on examproblems.com.