Three-phase power worksheet with answers

Free printable Three-phase power worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
ABCVL​ = 415 VIL​ = ?NZ = 9 + j12 Ωper phase

A balanced Y-connected load has an impedance of 9 + j12 Ω per phase. It is supplied from a balanced three-phase source with a line-to-line voltage of 415 V. Find the magnitude of the line current IL.

VL = 415 VZ = 9 + j12 Ω per phase
IL = A
2.Easy
ABCVL​ = 208 VIL​ = ?NZ = 18 + j24 Ωper phase

A balanced Y-connected load has an impedance of 18 + j24 Ω per phase. It is supplied from a balanced three-phase source with a line-to-line voltage of 208 V. Find the magnitude of the line current IL.

VL = 208 VZ = 18 + j24 Ω per phase
IL = A
3.Medium
ABCVL​ = 480 VNZ = 15 + j20 Ωper phase

A balanced Y-connected load with an impedance of 15 + j20 Ω per phase is connected to a balanced three-phase supply with a line-to-line voltage of 480 V. Find the total real power P absorbed by the load in kW.

VL = 480 VZ = 15 + j20 Ω per phase
P = kW
4.Medium
ABCVL​ = 400 VIL​ = ?M37 kW, η = 88%cos φ = 0.84

A three-phase induction motor delivers 37 kW of mechanical output power at full load. At this load its efficiency is 88% and its power factor is 0.84 lagging. The supply has a line-to-line voltage of 400 V. Find the line current IL.

Pout = 37 kWη = 88%cos φ = 0.84VL = 400 V
IL = A
5.Hard
P = 300 kWφ1​S1​Q2​QC​ = ?

A balanced three-phase load takes 300 kW at a power factor of 0.78 lagging from a 415 V (line-to-line), 50 Hz supply. A three-phase capacitor bank in parallel with the load must raise the overall power factor to 0.98 lagging. The real power stays the same. Find the total reactive power QC the capacitor bank must supply, in kvar.

P = 300 kWpf1 = 0.78pf2 = 0.98VL = 415 Vf = 50 Hz
QC = kvar
6.Hard
P = 50 kWφ1​S1​Q2​QC​ = ?

A balanced three-phase load takes 50 kW at a power factor of 0.7 lagging from a 480 V (line-to-line), 50 Hz supply. A three-phase capacitor bank in parallel with the load must raise the overall power factor to 0.9 lagging. The real power stays the same. Find the total reactive power QC the capacitor bank must supply, in kvar.

P = 50 kWpf1 = 0.7pf2 = 0.9VL = 480 Vf = 50 Hz
QC = kvar

Answer key

  1. 1. IL = 15.97 A
  2. 2. IL = 4.003 A
  3. 3. P = 5.53 kW
  4. 4. IL = 72.25 A
  5. 5. QC = 179.8 kvar
  6. 6. QC = 26.79 kvar

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