A solid circular shaft carries a torque T. Find the maximum shear stress τmax in the shaft.
Torsion of shafts worksheet with answers
1.Easy
T = 250 N·md = 20 mm
τmax = MPa
2.Easy
A hollow circular shaft with outer diameter 40 mm and inner diameter 30 mm carries a torque of 1500 N·m. Find the maximum shear stress τmax.
T = 1500 N·mdo = 40 mmdi = 30 mm
τmax = MPa
3.Medium
A solid steel shaft is fixed at the wall and twisted by a torque T at its free end. Find the angle of twist φ of the free end, in degrees.
T = 250 N·md = 50 mmL = 2.5 mG = 80 GPa
φ = °
4.Medium
A solid aluminium shaft 1 m long carries a torque of 2000 N·m. The angle of twist between its ends must not exceed 1.5°. Find the smallest diameter d that meets this limit.
T = 2000 N·mL = 1 mG = 26 GPaφallow = 1.5°
d = mm
5.Hard
A solid shaft must transmit 30 kW at 1450 rpm without the shear stress exceeding 40 MPa. Find the smallest diameter d that works.
P = 30 kWN = 1450 rpmτallow = 40 MPa
d = mm
6.Hard
A hollow shaft transmits 15 kW at 750 rpm. Find the maximum shear stress τmax in the shaft.
P = 15 kWN = 750 rpmdo = 80 mmdi = 64 mm
τmax = MPa
Answer key
- 1. τmax = 159.2 MPa
- 2. τmax = 174.6 MPa
- 3. φ = 0.7295 °
- 4. d = 73.96 mm
- 5. d = 29.3 mm
- 6. τmax = 3.218 MPa
Full step-by-step solutions: practise this topic on examproblems.com.