A solid circular shaft of diameter 20 mm is made of a material with an allowable shear stress of 70 MPa. Find the largest torque Tmax the shaft can carry.
Torsion of shafts worksheet with answers
1.Easy
d = 20 mmτallow = 70 MPa
Tmax = N·m
2.Easy
A solid circular shaft carries a torque T. Find the maximum shear stress τmax in the shaft.
T = 400 N·md = 40 mm
τmax = MPa
3.Medium
A solid aluminium shaft 1 m long carries a torque of 500 N·m. The angle of twist between its ends must not exceed 0.5°. Find the smallest diameter d that meets this limit.
T = 500 N·mL = 1 mG = 26 GPaφallow = 0.5°
d = mm
4.Medium
A solid steel shaft is fixed at the wall and twisted by a torque T at its free end. Find the angle of twist φ of the free end, in degrees.
T = 250 N·md = 30 mmL = 3 mG = 80 GPa
φ = °
5.Hard
A hollow shaft transmits 75 kW at 500 rpm. Find the maximum shear stress τmax in the shaft.
P = 75 kWN = 500 rpmdo = 80 mmdi = 60 mm
τmax = MPa
6.Hard
A hollow shaft must transmit 5 kW at 500 rpm. Its inner diameter is to be 0.5 times its outer diameter, and the shear stress must not exceed 80 MPa. Find the smallest outer diameter do.
P = 5 kWN = 500 rpmdi/do = 0.5τallow = 80 MPa
do = mm
Answer key
- 1. Tmax = 110 N·m
- 2. τmax = 31.83 MPa
- 3. d = 68.83 mm
- 4. φ = 6.755 °
- 5. τmax = 20.84 MPa
- 6. do = 18.65 mm
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