Transformers worksheet with answers

Free printable Transformers worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
N1​ = 300N2​ = ?460 V230 V

An ideal transformer must step 460 V down to 230 V. Its primary winding has 300 turns. How many turns N2 does the secondary winding need?

V1 = 460 VV2 = 230 VN1 = 300
N2 =
2.Easy
N1​ = 1600N2​ = 409600 VV2​ = ?

An ideal transformer has 1600 turns on its primary winding and 40 turns on its secondary winding. The primary is connected to a 9600 V AC supply. Find the secondary voltage V2.

N1 = 1600N2 = 40V1 = 9600 V
V2 = V
3.Medium
RL​ = 4 Ω1011200 VV2​I1​ = ?I2​

An ideal transformer with a turns ratio N₁:N₂ = 10:1 has 1200 V applied to its primary winding. A 4 Ω resistor is connected across the secondary winding. Find the primary current I1.

N1:N2 = 10:1V1 = 1200 VRL = 4 Ω
I1 = A
4.Medium
8 ΩN1​N2​512 Ω

An amplifier with an output resistance of 512 Ω drives an 8 Ω loudspeaker through an ideal transformer. For maximum power transfer the loudspeaker must look like 512 Ω from the amplifier. Find the turns ratio a = N₁/N₂.

Rs = 512 ΩRL = 8 Ω
a =
5.Hard
pf 0.95250 kVA, η = 98.2%

A single-phase 250 kVA transformer has a core loss of 2000 W. At rated load and a power factor of 0.95 lagging its efficiency is 98.2%. Find the full-load copper loss Pcu,fl in watts.

S = 250 kVAPcore = 2000 Wpf = 0.95η = 98.2%
Pcu,fl = W
6.Hard
pf 0.925 kVA, η = 98%

A single-phase 25 kVA transformer has a core loss of 100 W. At rated load and a power factor of 0.9 lagging its efficiency is 98%. Find the full-load copper loss Pcu,fl in watts.

S = 25 kVAPcore = 100 Wpf = 0.9η = 98%
Pcu,fl = W

Answer key

  1. 1. N2 = 150
  2. 2. V2 = 240 V
  3. 3. I1 = 3 A
  4. 4. a = 8
  5. 5. Pcu,fl = 2353 W
  6. 6. Pcu,fl = 359.2 W

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