Transformers worksheet with answers

Free printable Transformers worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
N1​ = 960N2​ = 601920 VV2​ = ?

An ideal transformer has 960 turns on its primary winding and 60 turns on its secondary winding. The primary is connected to a 1920 V AC supply. Find the secondary voltage V2.

N1 = 960N2 = 60V1 = 1920 V
V2 = V
2.Easy
N1​ = 3000N2​ = 12010000 VV2​ = ?

An ideal transformer has 3000 turns on its primary winding and 120 turns on its secondary winding. The primary is connected to a 10000 V AC supply. Find the secondary voltage V2.

N1 = 3000N2 = 120V1 = 10000 V
V2 = V
3.Medium
4160 V480 VIHV​ILV​ = ?250 kVA

A single-phase 250 kVA, 4160/480 V transformer operates at its rated load. Treat it as ideal. Find the current ILV in the low-voltage winding.

S = 250 kVAV1 = 4160 VV2 = 480 V
ILV = A
4.Medium
RL​ = 8 Ω2014800 VV2​I1​ = ?I2​

An ideal transformer with a turns ratio N₁:N₂ = 20:1 has 4800 V applied to its primary winding. An 8 Ω resistor is connected across the secondary winding. Find the primary current I1.

N1:N2 = 20:1V1 = 4800 VRL = 8 Ω
I1 = A
5.Hard
pf 0.8525 kVA, 50% load

A single-phase 25 kVA transformer has a core loss of 200 W and a copper loss of 300 W at rated load. It supplies 50% of its rated kVA at a power factor of 0.85 lagging. Find the total losses Ploss in watts at this load.

S = 25 kVAPcore = 200 WPcu,fl = 300 Wx = 0.5pf = 0.85
Ploss = W
6.Hard
pf 0.8500 kVA, η = 98.8%

A single-phase 500 kVA transformer has a core loss of 1500 W. At rated load and a power factor of 0.8 lagging its efficiency is 98.8%. Find the full-load copper loss Pcu,fl in watts.

S = 500 kVAPcore = 1500 Wpf = 0.8η = 98.8%
Pcu,fl = W

Answer key

  1. 1. V2 = 120 V
  2. 2. V2 = 400 V
  3. 3. ILV = 520.8 A
  4. 4. I1 = 1.5 A
  5. 5. Ploss = 275 W
  6. 6. Pcu,fl = 3358 W

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