Transformers worksheet with answers

Free printable Transformers worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
N1​ = 640N2​ = 403840 VV2​ = ?

An ideal transformer has 640 turns on its primary winding and 40 turns on its secondary winding. The primary is connected to a 3840 V AC supply. Find the secondary voltage V2.

N1 = 640N2 = 40V1 = 3840 V
V2 = V
2.Easy
N1​ = 8000N2​ = ?9200 V230 V

An ideal transformer must step 9200 V down to 230 V. Its primary winding has 8000 turns. How many turns N2 does the secondary winding need?

V1 = 9200 VV2 = 230 VN1 = 8000
N2 =
3.Medium
16 ΩN1​N2​64 Ω

An amplifier with an output resistance of 64 Ω drives a 16 Ω loudspeaker through an ideal transformer. For maximum power transfer the loudspeaker must look like 64 Ω from the amplifier. Find the turns ratio a = N₁/N₂.

Rs = 64 ΩRL = 16 Ω
a =
4.Medium
7200 V240 VIHV​ILV​ = ?100 kVA

A single-phase 100 kVA, 7200/240 V transformer operates at its rated load. Treat it as ideal. Find the current ILV in the low-voltage winding.

S = 100 kVAV1 = 7200 VV2 = 240 V
ILV = A
5.Hard
500 kVA

A single-phase 500 kVA transformer has a core loss of 2000 W and a copper loss of 4000 W at rated load. At what load Sη,max, in kVA, is its efficiency highest?

S = 500 kVAPcore = 2000 WPcu,fl = 4000 W
Sη,max = kVA
6.Hard
pf 0.9150 kVA, η = 97.5%

A single-phase 150 kVA transformer has a core loss of 1200 W. At rated load and a power factor of 0.9 lagging its efficiency is 97.5%. Find the full-load copper loss Pcu,fl in watts.

S = 150 kVAPcore = 1200 Wpf = 0.9η = 97.5%
Pcu,fl = W

Answer key

  1. 1. V2 = 240 V
  2. 2. N2 = 200
  3. 3. a = 2
  4. 4. ILV = 416.7 A
  5. 5. Sη,max = 353.6 kVA
  6. 6. Pcu,fl = 2262 W

Full step-by-step solutions: practise this topic on examproblems.com.