Transformers worksheet with answers

Free printable Transformers worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
N1​ = 160N2​ = ?960 V120 V

An ideal transformer must step 960 V down to 120 V. Its primary winding has 160 turns. How many turns N2 does the secondary winding need?

V1 = 960 VV2 = 120 VN1 = 160
N2 =
2.Easy
N1​ = 80N2​ = 320230 VV2​ = ?

An ideal transformer has 80 turns on its primary winding and 320 turns on its secondary winding. The primary is connected to a 230 V AC supply. Find the secondary voltage V2.

N1 = 80N2 = 320V1 = 230 V
V2 = V
3.Medium
RL​ = 4 Ω1011200 VV2​I1​ = ?I2​

An ideal transformer with a turns ratio N₁:N₂ = 10:1 has 1200 V applied to its primary winding. A 4 Ω resistor is connected across the secondary winding. Find the primary current I1.

N1:N2 = 10:1V1 = 1200 VRL = 4 Ω
I1 = A
4.Medium
4800 V240 VIHV​ILV​ = ?250 kVA

A single-phase 250 kVA, 4800/240 V transformer operates at its rated load. Treat it as ideal. Find the current ILV in the low-voltage winding.

S = 250 kVAV1 = 4800 VV2 = 240 V
ILV = A
5.Hard
pf 0.8575 kVA, 25% load

A single-phase 75 kVA transformer has a core loss of 225 W and a copper loss of 562.5 W at rated load. It supplies 25% of its rated kVA at a power factor of 0.85 lagging. Find the total losses Ploss in watts at this load.

S = 75 kVAPcore = 225 WPcu,fl = 562.5 Wx = 0.25pf = 0.85
Ploss = W
6.Hard
pf 0.85500 kVA, η = 98.8%

A single-phase 500 kVA transformer has a core loss of 1500 W. At rated load and a power factor of 0.85 lagging its efficiency is 98.8%. Find the full-load copper loss Pcu,fl in watts.

S = 500 kVAPcore = 1500 Wpf = 0.85η = 98.8%
Pcu,fl = W

Answer key

  1. 1. N2 = 20
  2. 2. V2 = 920 V
  3. 3. I1 = 3 A
  4. 4. ILV = 1042 A
  5. 5. Ploss = 260.2 W
  6. 6. Pcu,fl = 3662 W

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