Transformers worksheet with answers

Free printable Transformers worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
N1​ = 160N2​ = ?960 V120 V

An ideal transformer must step 960 V down to 120 V. Its primary winding has 160 turns. How many turns N2 does the secondary winding need?

V1 = 960 VV2 = 120 VN1 = 160
N2 =
2.Easy
N1​ = 1000N2​ = ?4600 V230 V

An ideal transformer must step 4600 V down to 230 V. Its primary winding has 1000 turns. How many turns N2 does the secondary winding need?

V1 = 4600 VV2 = 230 VN1 = 1000
N2 =
3.Medium
10 ΩN1​N2​640 Ω

An amplifier with an output resistance of 640 Ω drives a 10 Ω loudspeaker through an ideal transformer. For maximum power transfer the loudspeaker must look like 640 Ω from the amplifier. Find the turns ratio a = N₁/N₂.

Rs = 640 ΩRL = 10 Ω
a =
4.Medium
50 Ω41

A 50 Ω resistor is connected across the secondary winding of an ideal transformer with a turns ratio N₁:N₂ = 4:1. Find the resistance R1′ seen looking into the primary winding.

N1:N2 = 4:1RL = 50 Ω
R1′ = Ω
5.Hard
pf 0.975 kVA, η = 97%

A single-phase 75 kVA transformer has a core loss of 600 W. At rated load and a power factor of 0.9 lagging its efficiency is 97%. Find the full-load copper loss Pcu,fl in watts.

S = 75 kVAPcore = 600 Wpf = 0.9η = 97%
Pcu,fl = W
6.Hard
pf 0.9525 kVA, η = 97.5%

A single-phase 25 kVA transformer has a core loss of 125 W. At rated load and a power factor of 0.95 lagging its efficiency is 97.5%. Find the full-load copper loss Pcu,fl in watts.

S = 25 kVAPcore = 125 Wpf = 0.95η = 97.5%
Pcu,fl = W

Answer key

  1. 1. N2 = 20
  2. 2. N2 = 50
  3. 3. a = 8
  4. 4. R1′ = 800 Ω
  5. 5. Pcu,fl = 1488 W
  6. 6. Pcu,fl = 484 W

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