Transformers worksheet with answers

Free printable Transformers worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
N1​ = 800N2​ = ?4600 V230 V

An ideal transformer must step 4600 V down to 230 V. Its primary winding has 800 turns. How many turns N2 does the secondary winding need?

V1 = 4600 VV2 = 230 VN1 = 800
N2 =
2.Easy
N1​ = 240N2​ = ?460 V230 V

An ideal transformer must step 460 V down to 230 V. Its primary winding has 240 turns. How many turns N2 does the secondary winding need?

V1 = 460 VV2 = 230 VN1 = 240
N2 =
3.Medium
5 Ω121

A 5 Ω resistor is connected across the secondary winding of an ideal transformer with a turns ratio N₁:N₂ = 12:1. Find the resistance R1′ seen looking into the primary winding.

N1:N2 = 12:1RL = 5 Ω
R1′ = Ω
4.Medium
11000 V400 VIHV​ = ?ILV​15 kVA

A single-phase 15 kVA, 11000/400 V transformer operates at its rated load. Treat it as ideal. Find the current IHV in the high-voltage winding.

S = 15 kVAV1 = 11000 VV2 = 400 V
IHV = A
5.Hard
pf 0.925 kVA, 25% load

A single-phase 25 kVA transformer has a core loss of 75 W and a copper loss of 225 W at rated load. It supplies 25% of its rated kVA at a power factor of 0.9 lagging. Find the total losses Ploss in watts at this load.

S = 25 kVAPcore = 75 WPcu,fl = 225 Wx = 0.25pf = 0.9
Ploss = W
6.Hard
pf 0.975 kVA, η = 98%

A single-phase 75 kVA transformer has a core loss of 300 W. At rated load and a power factor of 0.9 lagging its efficiency is 98%. Find the full-load copper loss Pcu,fl in watts.

S = 75 kVAPcore = 300 Wpf = 0.9η = 98%
Pcu,fl = W

Answer key

  1. 1. N2 = 40
  2. 2. N2 = 120
  3. 3. R1′ = 720 Ω
  4. 4. IHV = 1.364 A
  5. 5. Ploss = 89.06 W
  6. 6. Pcu,fl = 1078 W

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