Transformers worksheet with answers

Free printable Transformers worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
N1​ = 100N2​ = 400690 VV2​ = ?

An ideal transformer has 100 turns on its primary winding and 400 turns on its secondary winding. The primary is connected to a 690 V AC supply. Find the secondary voltage V2.

N1 = 100N2 = 400V1 = 690 V
V2 = V
2.Easy
N1​ = 120N2​ = 1200240 VV2​ = ?

An ideal transformer has 120 turns on its primary winding and 1200 turns on its secondary winding. The primary is connected to a 240 V AC supply. Find the secondary voltage V2.

N1 = 120N2 = 1200V1 = 240 V
V2 = V
3.Medium
480 V240 VIHV​ = ?ILV​150 kVA

A single-phase 150 kVA, 480/240 V transformer operates at its rated load. Treat it as ideal. Find the current IHV in the high-voltage winding.

S = 150 kVAV1 = 480 VV2 = 240 V
IHV = A
4.Medium
50 Ω121

A 50 Ω resistor is connected across the secondary winding of an ideal transformer with a turns ratio N₁:N₂ = 12:1. Find the resistance R1′ seen looking into the primary winding.

N1:N2 = 12:1RL = 50 Ω
R1′ = Ω
5.Hard
pf 0.95100 kVA, 75% load

A single-phase 100 kVA transformer has a core loss of 400 W and a copper loss of 1200 W at rated load. It supplies 75% of its rated kVA at a power factor of 0.95 lagging. Find the total losses Ploss in watts at this load.

S = 100 kVAPcore = 400 WPcu,fl = 1200 Wx = 0.75pf = 0.95
Ploss = W
6.Hard
pf 0.950 kVA, η = 98.8%

A single-phase 50 kVA transformer has a core loss of 200 W. At rated load and a power factor of 0.9 lagging its efficiency is 98.8%. Find the full-load copper loss Pcu,fl in watts.

S = 50 kVAPcore = 200 Wpf = 0.9η = 98.8%
Pcu,fl = W

Answer key

  1. 1. V2 = 2760 V
  2. 2. V2 = 2400 V
  3. 3. IHV = 312.5 A
  4. 4. R1′ = 7200 Ω
  5. 5. Ploss = 1075 W
  6. 6. Pcu,fl = 346.6 W

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