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Name: ____________________ Date: ____________
1.Easy
Exactly one member of this truss carries no force under these loads. Which is the zero-force member? Click it in the diagram.
B: 10 kN ↓C: 25 kN ↓F: 40 kN ↓G: 25 kN ↓
1member AB
2member BC
3member CD
4member DE
5member FG
6member GH
7member AF
8member HE
9member BF
10member CG
11member DH
12member FC
13member HC
2.Easy
Use the method of joints to find the force FAB in member AB. Give tension as positive and compression as negative.
span = 8 mheight = 2 mB is 4 m from Avertical load = 55 kN
FAB = kN
3.Medium
Use the method of joints to find the force FAC in member AC. Give tension as positive and compression as negative.
span = 4 mheight = 4 mB is 3 m from Avertical load = 50 kN
FAC = kN
4.Medium
Use the method of joints to find the force FBC in member BC. Give tension as positive and compression as negative.
span = 4 mheight = 4 mB is 1 m from Avertical load = 45 kN
FBC = kN
5.Hard
Use the method of joints to find the force FAB in member AB. Give tension as positive and compression as negative.
span = 8 mheight = 2 mB is 1 m from Avertical load = 60 kNhorizontal load = 25 kN →
FAB = kN
6.Hard
Use the method of joints to find the force FAC in member AC. Give tension as positive and compression as negative.
span = 4 mheight = 3 mB is 1 m from Avertical load = 10 kNhorizontal load = 15 kN →
FAC = kN
Answer key
1. member DH
2. FAB = −61.49 kN
3. FAC = 9.375 kN
4. FBC = −14.06 kN
5. FAB = −51.71 kN
6. FAC = 13.75 kN
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