Use the method of joints to find the force FAB in member AB. Give tension as positive and compression as negative.
Truss: method of joints worksheet with answers
1.Easy
span = 4 mheight = 2 mB is 2 m from Avertical load = 60 kN
FAB = kN
2.Easy
Use the method of joints to find the force FAC in member AC. Give tension as positive and compression as negative.
span = 8 mheight = 2 mB is 4 m from Avertical load = 60 kN
FAC = kN
3.Medium
Exactly one member of this truss carries no force under these loads. Which is the zero-force member? Click it in the diagram.
F: 40 kN ↓H: 35 kN ↓
- 1member AB
- 2member BC
- 3member CD
- 4member DE
- 5member FG
- 6member GH
- 7member AF
- 8member HE
- 9member BF
- 10member CG
- 11member DH
- 12member BG
- 13member DG
4.Medium
Use the method of joints to find the force FBC in member BC. Give tension as positive and compression as negative.
span = 8 mheight = 3 mB is 7 m from Avertical load = 35 kN
FBC = kN
5.Hard
Exactly one member of this truss carries no force under these loads. Which is the zero-force member? Click it in the diagram.
D: 40 kN ↓F: 25 kN ↓H: 30 kN ↓H: 35 kN ←
- 1member AB
- 2member BC
- 3member CD
- 4member DE
- 5member FG
- 6member GH
- 7member AF
- 8member HE
- 9member BF
- 10member CG
- 11member DH
- 12member BG
- 13member DG
6.Hard
Use the method of joints to find the force FBC in member BC. Give tension as positive and compression as negative.
span = 4 mheight = 4 mB is 1 m from Avertical load = 25 kNhorizontal load = 15 kN →
FBC = kN
Answer key
- 1. FAB = −42.43 kN
- 2. FAC = 60 kN
- 3. member CG
- 4. FBC = −32.28 kN
- 5. member CG
- 6. FBC = −26.56 kN
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