Use the method of joints to find the force FBC in member BC. Give tension as positive and compression as negative.
Truss: method of joints worksheet with answers
1.Easy
span = 4 mheight = 4 mB is 2 m from Avertical load = 20 kN
FBC = kN
2.Easy
Exactly one member of this truss carries no force under these loads. Which is the zero-force member? Click it in the diagram.
D: 40 kN ↓F: 35 kN ↓G: 20 kN ↓
- 1member AB
- 2member BC
- 3member CD
- 4member DE
- 5member FG
- 6member GH
- 7member AF
- 8member HE
- 9member BF
- 10member CG
- 11member DH
- 12member FC
- 13member HC
3.Medium
Use the method of joints to find the force FAC in member AC. Give tension as positive and compression as negative.
span = 5 mheight = 4 mB is 3 m from Avertical load = 45 kN
FAC = kN
4.Medium
Use the method of joints to find the force FAB in member AB. Give tension as positive and compression as negative.
span = 5 mheight = 4 mB is 4 m from Avertical load = 10 kN
FAB = kN
5.Hard
Exactly one member of this truss carries no force under these loads. Which is the zero-force member? Click it in the diagram.
H: 15 kN ↓H: 40 kN ←
- 1member AB
- 2member BC
- 3member CD
- 4member DE
- 5member FG
- 6member GH
- 7member AF
- 8member HE
- 9member BF
- 10member CG
- 11member DH
- 12member BG
- 13member DG
6.Hard
Use the method of joints to find the force FBC in member BC. Give tension as positive and compression as negative.
span = 6 mheight = 4 mB is 4 m from Avertical load = 10 kNhorizontal load = 25 kN →
FBC = kN
Answer key
- 1. FBC = −11.18 kN
- 2. member BF
- 3. FAC = 13.5 kN
- 4. FAB = −2.828 kN
- 5. member CG
- 6. FBC = −26.09 kN
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