A force of 290 N acts in the xy-plane at 280° measured anticlockwise from the positive x-axis. Find its y-component Fy.
Vectors: dot & cross product worksheet with answers
1.Easy
F = 290 Nθ = 280°
Fy = N
2.Easy
Find the magnitude |a| of the vector a = (11, 8).
a = (11, 8)
|a| =
3.Medium
Find the scalar projection compb a of a = (7, 5, 4) onto b = (−2, 4, 6), that is, the component of a in the direction of b.
a = (7, 5, 4)b = (−2, 4, 6)
compb a =
4.Medium
A constant force F = (−10, 25, 0) N acts on an object while it moves in a straight line from point A(1, 1, −4) to point B(4, 0, 0). Coordinates are in metres. Find the work W done by the force.
F = (−10, 25, 0) NA(1, 1, −4) mB(4, 0, 0) m
W = J
5.Hard
For a = (−5, 4, 1) and b = (2, 4, 2), find the x-component (a × b)x of the cross product a × b.
a = (−5, 4, 1)b = (2, 4, 2)
(a × b)x =
6.Hard
For a = (−2, −2, −5) and b = (−4, −2, −3), find the x-component (a × b)x of the cross product a × b.
a = (−2, −2, −5)b = (−4, −2, −3)
(a × b)x =
Answer key
- 1. Fy = −285.6 N
- 2. |a| = 13.6
- 3. compb a = 4.009
- 4. W = −55 J
- 5. (a × b)x = 4
- 6. (a × b)x = −4
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