A force of 40 N acts in the xy-plane at 330° measured anticlockwise from the positive x-axis. Find its x-component Fx.
Vectors: dot & cross product worksheet with answers
1.Easy
F = 40 Nθ = 330°
Fx = N
2.Easy
Find the y-component ûy of the unit vector û that points in the direction of a = (−4, 6, −7).
a = (−4, 6, −7)
ûy =
3.Medium
Find the scalar projection compb a of a = (−1, 0, −7) onto b = (1, 4, −1), that is, the component of a in the direction of b.
a = (−1, 0, −7)b = (1, 4, −1)
compb a =
4.Medium
Find the scalar projection compb a of a = (6, 4, −1) onto b = (0, −4, −5), that is, the component of a in the direction of b.
a = (6, 4, −1)b = (0, −4, −5)
compb a =
5.Hard
For a = (−1, −4, −4) and b = (6, −1, 3), find the y-component (a × b)y of the cross product a × b.
a = (−1, −4, −4)b = (6, −1, 3)
(a × b)y =
6.Hard
A force F = (40, 20, 60) N acts at point A(−3, −2, −2). Coordinates are in metres. Find the magnitude |M| of the moment of the force about the origin O(0, 0, 0).
F = (40, 20, 60) NA(−3, −2, −2) mO(0, 0, 0) m
|M| = N·m
Answer key
- 1. Fx = 34.64 N
- 2. ûy = 0.597
- 3. compb a = 1.414
- 4. compb a = −1.718
- 5. (a × b)y = −21
- 6. |M| = 129.6 N·m
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