Find the magnitude |a| of the vector a = (−8, −1, 2).
Vectors: dot & cross product worksheet with answers
1.Easy
a = (−8, −1, 2)
|a| =
2.Easy
A force of 270 N acts in the xy-plane at 235° measured anticlockwise from the positive x-axis. Find its x-component Fx.
F = 270 Nθ = 235°
Fx = N
3.Medium
Find the value of k for which the vectors a = (−5, 2, 3) and b = (0, 5, k) are perpendicular.
a = (−5, 2, 3)b = (0, 5, k)
k =
4.Medium
Find the value of k for which the vectors a = (−1, 6, 4) and b = (−4, 2, k) are perpendicular.
a = (−1, 6, 4)b = (−4, 2, k)
k =
5.Hard
For a = (−5, −5, 4) and b = (0, −5, −1), find the y-component (a × b)y of the cross product a × b.
a = (−5, −5, 4)b = (0, −5, −1)
(a × b)y =
6.Hard
The unit vector n̂ is perpendicular to both a = (−3, 4, 3) and b = (−4, 1, 3) and has a positive z-component. Find its x-component n̂x.
a = (−3, 4, 3)b = (−4, 1, 3)n̂z > 0
n̂x =
Answer key
- 1. |a| = 8.307
- 2. Fx = −154.9 N
- 3. k = −3.333
- 4. k = −4
- 5. (a × b)y = −5
- 6. n̂x = 0.5592
Full step-by-step solutions: practise this topic on examproblems.com.