A force of 40 N acts in the xy-plane at 85° measured anticlockwise from the positive x-axis. Find its y-component Fy.
Vectors: dot & cross product worksheet with answers
1.Easy
F = 40 Nθ = 85°
Fy = N
2.Easy
Find the magnitude |a| of the vector a = (3, 0, 8).
a = (3, 0, 8)
|a| =
3.Medium
Find the dot product a·b of a = (0, −6, −5) and b = (−2, 5, −3).
a = (0, −6, −5)b = (−2, 5, −3)
a·b =
4.Medium
Find the scalar projection compb a of a = (−2, −1, 5) onto b = (2, 5, 4), that is, the component of a in the direction of b.
a = (−2, −1, 5)b = (2, 5, 4)
compb a =
5.Hard
A force F = (60, −40, 50) N acts at point A(−2, −2, −1). Coordinates are in metres. Find the x-component Mx of the moment of the force about point O(−1, 2, 3).
F = (60, −40, 50) NA(−2, −2, −1) mO(−1, 2, 3) m
Mx = N·m
6.Hard
For a = (1, −4, −1) and b = (−2, 6, −2), find the y-component (a × b)y of the cross product a × b.
a = (1, −4, −1)b = (−2, 6, −2)
(a × b)y =
Answer key
- 1. Fy = 39.85 N
- 2. |a| = 8.544
- 3. a·b = −15
- 4. compb a = 1.64
- 5. Mx = −360 N·m
- 6. (a × b)y = 4
Full step-by-step solutions: practise this topic on examproblems.com.