Two forces act at a point in the xy-plane: F₁ = 130 N at 10° and F₂ = 210 N at 295°, both measured anticlockwise from the positive x-axis. Find the direction φ of their resultant, measured anticlockwise from the positive x-axis (between 0° and 360°).
Vectors: dot & cross product worksheet with answers
1.Easy
F1 = 130 N, θ1 = 10°F2 = 210 N, θ2 = 295°
φ = °
2.Easy
A force of 300 N acts in the xy-plane at 20° measured anticlockwise from the positive x-axis. Find its y-component Fy.
F = 300 Nθ = 20°
Fy = N
3.Medium
Find the scalar projection compb a of a = (−2, −2, −2) onto b = (4, −4, −2), that is, the component of a in the direction of b.
a = (−2, −2, −2)b = (4, −4, −2)
compb a =
4.Medium
A constant force F = (10, −30, −5) N acts on an object while it moves in a straight line from point A(−2, −5, −2) to point B(−5, −5, 4). Coordinates are in metres. Find the work W done by the force.
F = (10, −30, −5) NA(−2, −5, −2) mB(−5, −5, 4) m
W = J
5.Hard
The unit vector n̂ is perpendicular to both a = (−4, −1, 4) and b = (−4, 5, −2) and has a positive z-component. Find its y-component n̂y.
a = (−4, −1, 4)b = (−4, 5, −2)n̂z > 0
n̂y =
6.Hard
For a = (−2, 3, 1) and b = (−1, −5, 0), find the z-component (a × b)z of the cross product a × b.
a = (−2, 3, 1)b = (−1, −5, 0)
(a × b)z =
Answer key
- 1. φ = 322.3 °
- 2. Fy = 102.6 N
- 3. compb a = 0.6667
- 4. W = −60 J
- 5. n̂y = 0.6247
- 6. (a × b)z = 13
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