Laplace transform calculator

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Result

F(s)6/(s + 2)³ + 20/(s² + 16) − 2(s + 1)/((s + 1)² + 9) + e−s·4/s
Region of convergenceRe(s) > 0

Find the Laplace transform of a function made of common terms: powers of t, exponentials, sines and cosines (with a phase), sinh and cosh, shifted step functions u(t − c) and impulses δ(t − c). The calculator transforms each term with the standard table and the shift theorems, shows which entries it used, and gives F(s) with its region of convergence.

Step-by-step solution

Transform each term

L{3t2·e−2t} → 6/(s + 2)³
L{5sin(4t)} → 20/(s² + 16)
L{−2e−t·cos(3t)} → −2(s + 1)/((s + 1)² + 9)
L{4u(t − 1)} → e−s·4/s

Table entries used

L{tneat} = n!/(s − a)n+1
L{eat sin ωt} = ω/((s − a)² + ω²)
L{eat cos ωt} = (s − a)/((s − a)² + ω²)
L{g(t)·u(t − c)} = e−cs·L{g(t + c)}

Add the transforms (linearity)

F(s) = 6/(s + 2)³ + 20/(s² + 16) − 2(s + 1)/((s + 1)² + 9) + e−s·4/s

How to find a Laplace transform with the table

  1. Split f(t) into a sum of terms; the Laplace transform is linear.
  2. Use the basic pairs: L{tⁿ} = n!/sⁿ⁺¹, L{sin ωt} = ω/(s² + ω²) and L{cos ωt} = s/(s² + ω²).
  3. Multiplying by e^(at) shifts s: L{e^(at) f(t)} = F(s − a).
  4. A delayed term g(t)·u(t − c) transforms to e^(−cs)·L{g(t + c)}.
  5. Add the transforms of the terms; F(s) exists for Re(s) larger than the largest exponent a.

Questions and answers

How do I type f(t)?

For example 3t^2 e^(-2t) + 5sin(4t) - 2e^(-t)cos(3t) + 4u(t-1). Use ^ for powers, e^(at) or exp(at) for exponentials, u(t-c) for a step and δ(t-c) or delta(t-c) for an impulse. A phase is allowed, as in sin(2t + 1).

What is the difference between t·u(t − 1) and (t − 1)·u(t − 1)?

The second is a delayed ramp and transforms to e^(−s)/s². The first is t·u(t − 1) = ((t − 1) + 1)·u(t − 1), which transforms to e^(−s)(1/s² + 1/s). The calculator handles both by writing g(t + c).

How are t·sin(ωt) and t·cos(ωt) transformed?

Through L{tⁿ e^(jωt)} = n!/(s − jω)ⁿ⁺¹: the imaginary part gives the sine and the real part the cosine, for example L{t sin ωt} = 2ωs/(s² + ω²)².

What is the region of convergence?

The values of s for which the transform integral converges: Re(s) larger than the largest growth rate in f(t). For e^(3t) that is Re(s) > 3.

Can I enter a product of two sines?

Not directly. Rewrite it first with a product-to-sum identity, for example sin(at)·cos(bt) = ½[sin((a + b)t) + sin((a − b)t)].

Practise it yourself

Practise Laplace transforms

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