Axial stress and strain calculator

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Result

Normal stress159.2 MPa
Strain0.0007958
Elongation1.592 mm

Step-by-step solution

Cross-section

A = πd²/4 = 314.2 mm²

Stress, strain and elongation

σ = F/A = 50000/314.2 = 159.2 MPa
ε = σ/E = 0.0007958
ΔL = ε·L = 1.592 mm

Key formulas

Normal stress
σ = F/A
Strain
ε = ΔL/L
Hooke’s law
σ = E·ε
Elongation
ΔL = FL/(EA)
Thermal strain
εT = α·ΔT

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