You need €25 000 in 8 years. An account pays 3% per year, compounded monthly. How much must you deposit today? Find the present value PV.
FV = €25 0003% / 12n = 8
PV = €
2.Time value of moneyHard
You deposit €1 000 at the start of every year for 10 years, the first deposit today. The account pays 3% per year. How much is in the account at the end of year 10? Find FV.
A = €1 000i = 3%n = 10
FV = €
3.NPV & IRRMedium
An investment of €60 000 gives these cash flows at the end of years 1 to 3: €20 000, €26 000, €25 000. The cost of capital is 10%. Find the net present value NPV.
A project costs €10 000 and returns €6 500, €6 000, €7 000 at the end of years 1 to 3. Find its internal rate of return IRR in percent.
CF0 = −10 000CF1 = 6 500CF2 = 6 000CF3 = 7 000
IRR = %
5.Bond pricing & yieldMedium
A bond with a face value of €1 000 pays an annual coupon of 3% and matures in 8 years. Its yield to maturity changes from 5.5% to 4%. By how much ΔP does the bond price change?
F = €1 000coupon = 3%n = 8y1 = 5.5%y2 = 4%
ΔP = €
6.Bond pricing & yieldHard
A bond with a face value of €1 000 and an annual coupon of 6% matures in 3 years and sells for €1 025. Find its yield to maturity YTM in percent.
F = €1 000coupon = 6%n = 3P = €1 025
YTM = %
7.CAPM & WACCMedium
A company has equity worth €6 000 000 and debt worth €2 000 000. Its WACC is 9.56%, its pre-tax cost of debt is 3% and the tax rate is 25.8%. Find the cost of equity re.
A company's shares have a beta of 1.2 at its current debt-to-equity ratio of 0.25. It plans to raise its debt-to-equity ratio to 1.25. The tax rate is 25%, the risk-free rate 1% and the market risk premium 4%. Find the cost of equity re after the change.
Find the sample standard deviation s of the data: 47, 35, 21, 10, 25.
n = 5
s =
10.Descriptive statisticsHard
A quantity is normally distributed with mean 60 and standard deviation 12. What proportion P of values is below 84?
μ = 60σ = 12x = 84
P =
11.ProbabilityMedium
A bag holds 8 red and 5 blue balls. You draw two balls without putting the first one back. What is the probability P that both are red?
8 / 5
P =
12.ProbabilityHard
A game costs €1 to play. You win €3 with probability 0.25 and €10 with probability 0.01; otherwise you win nothing. The stake is not returned. Find the expected net gain E(G) per game.
stake = €1€3: p = 0.25€10: p = 0.01
E(G) = €
13.Normal distributionMedium
The masses of bolts are independent and normal with mean 40 g and standard deviation 1.2 g. Find the probability P that the total mass of 4 of them exceeds 164.8 g. Round z to two decimals.
μ = 40 gσ = 1.2 gn = 4> 164.8 g
P =
14.Normal distributionHard
The heights of adult men are normally distributed with mean 178 cm and standard deviation 7 cm. Find the value x below which 75% of them lie (the 75th percentile).
μ = 178σ = 7P = 75%
x = cm
15.Confidence intervalsMedium
A sample of 8 items has mean 12.5 and standard deviation s = 18.5. The population is roughly normal. Find the margin of error E of a 90% confidence interval for the mean.
n = 8x̄ = 12.5s = 18.590%t(7) = 1.895
E =
16.Confidence intervalsHard
The population standard deviation is 15. How large a sample n do you need so that a 99% confidence interval for the mean has a margin of error of at most 2?
σ = 15E = 299%
n =
17.Hypothesis tests & confidence intervalsMedium
7 employees take a typing test before and after a training course. For each person the difference d = after − before (words per minute) is recorded. The mean difference is −5.65 and the standard deviation of the differences is 8.3. Find the paired test statistic t for H₀: μd = 0.
n = 7d̄ = −5.65sd = 8.3
t =
18.Hypothesis tests & confidence intervalsHard
How large must a sample be so that the 95% confidence interval for a mean has a margin of error of at most 2.5? The standard deviation is 8. Find the smallest sample size n.
σ = 8E = 2.595%
n =
19.Linear regression & correlationMedium
The table gives 5 paired observations of x = car age in years and y = price in k€. Their sums are given. Find Pearson's correlation coefficient r from these sums.
n = 5Σx = 15Σy = 106Σx² = 55Σy² = 2308Σxy = 294
r =
20.Linear regression & correlationHard
The table gives 6 paired observations of x = load in kN and y = extension in mm. Use the least-squares line ŷ = a + b·x. For which value x does the line predict ŷ = 15?
n = 6ŷ = 15
x =
3Solutions
1.Time value of money
Answer: PV = 19672 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Rate and number of periods
i = 0.03/12 = 0.0025
N = 12·8 = 96
Present value
PV = FV/(1 + i)N = 25 000/1.271 = €19 671.59
Answer
PV = €19 671.59
2.Time value of money
Answer: FV = 11808 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Ordinary annuity factor
((1 + 0.03)10 − 1)/0.03 = 11.46
Annuity due
Each deposit is invested one year longer.
FV = 1 000·11.46·1.03 = €11 807.80
Answer
FV = €11 807.80
3.NPV & IRR
Answer: NPV = −1548 €
Net present value: discount every cash flow back to today with the required rate of return r, then add them up: NPV = Σ CFₜ/(1 + r)ᵗ. A project with NPV > 0 earns more than r and adds value. The internal rate of return (IRR) is the rate at which NPV = 0.
Present value of each cash flow
CF0 = −60 000
CF1/(1 + 0.1)1 = 20 000/1.1 = 18 181.82
CF2/(1 + 0.1)2 = 26 000/1.21 = 21 487.60
CF3/(1 + 0.1)3 = 25 000/1.331 = 18 782.87
Add them up
NPV = €−1 547.71
Answer
NPV = €−1 547.71
NPV is negative, so the project earns less than the required return.
4.NPV & IRR
Answer: IRR = 41.98 %
Net present value: discount every cash flow back to today with the required rate of return r, then add them up: NPV = Σ CFₜ/(1 + r)ᵗ. A project with NPV > 0 earns more than r and adds value. The internal rate of return (IRR) is the rate at which NPV = 0.
Bracket the IRR
NPV falls as the rate rises, so the IRR lies between a rate with positive NPV and one with negative NPV.
NPV(40%) = 255.10
NPV(45%) = −367.38
Narrow down
Linear interpolation gives a first estimate; repeating it (or a calculator's IRR function) gives the exact rate.
IRR ≈ 40 + 5·255.10/(255.10 − (−367.38)) = 42.05%
exact: NPV(41.98%) = 0 → IRR = 41.98%
Answer
IRR = 41.98%
5.Bond pricing & yield
Answer: ΔP = 91.04 €
Bond pricing: a bond’s price is the present value of its cash flows, discounted at the yield to maturity (YTM): the coupons form an annuity and the face value is paid back at maturity. P = C·(1 − (1 + y)⁻ⁿ)/y + F/(1 + y)ⁿ. When the yield is above the coupon rate the bond trades below face value, and the other way round.
Bond pricing: a bond’s price is the present value of its cash flows, discounted at the yield to maturity (YTM): the coupons form an annuity and the face value is paid back at maturity. P = C·(1 − (1 + y)⁻ⁿ)/y + F/(1 + y)ⁿ. When the yield is above the coupon rate the bond trades below face value, and the other way round.
Equation for the yield
€1 025 = €60·(1 − (1 + y)⁻³)/y + €1 000/(1 + y)³
Solve numerically
P(5%) = €1 027.23, P(6%) = €1 000.00
YTM = 5.081%
Answer
YTM = 5.081%
7.CAPM & WACC
Answer: re = 12 %
Cost of capital: CAPM gives the return shareholders require: re = rf + β·(rm − rf). The weighted average cost of capital mixes equity and debt by their market values: WACC = E/V·re + D/V·rd·(1 − T), with V = E + D. Interest is tax-deductible, hence the (1 − T).
Weights
V = €8 000 000, E/V = 0.75, D/V = 0.25
Debt part of the WACC
0.25·3%·(1 − 0.258) = 0.5565%
Cost of equity
re = (9.56% − 0.5565%)/0.75 = 12%
Answer
re = 12%
8.CAPM & WACC
Answer: re = 8.832 %
Levered beta (Hamada): debt makes equity riskier. βL = βU·(1 + (1 − T)·D/E), where βU is the beta of the business without debt. To move a beta to another capital structure, unlever it first and then relever it at the new D/E.
Unlever the beta
βU = 1.2/(1 + 0.75·0.25) = 1.011
Relever at the new D/E
βL = 1.011·(1 + 0.75·1.25) = 1.958
Cost of equity (CAPM)
re = 1% + 1.958·4% = 8.832%
Answer
re = 8.832%
9.Descriptive statistics
Answer: s = 14.06
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Standardise
z = 2
Standard normal table
Φ(2) = 0.9772
P = 0.9772
Answer
P = 0.9772
11.Probability
Answer: P = 0.359
Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.
First and second draw
P = 8/13 · 7/12 = 56/156 = 0.359
Answer
P = 0.359
12.Probability
Answer: E(G) = −0.15 €
Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.
Net outcomes
G: 2 (p = 0.25), 9 (p = 0.01), −1 (p = 0.74)
Expected value
E(G) = 2·0.25 + 9·0.01 − 1·0.74 = −0.15 €
Answer
E(G) = −0.15 €
A negative value means you lose money on average.
13.Normal distribution
Answer: P = 0.02275
Sums and differences of normal variables: if X and Y are independent and normal, X + Y and X − Y are normal too. Means add or subtract: E(X ± Y) = μX ± μY. Variances always add, also for a difference: Var(X ± Y) = σX² + σY², so σ = √(σX² + σY²). Standard deviations never add directly. The total of n independent items with the same distribution has mean n·μ and standard deviation σ·√n. Then standardise as usual: z = (x − mean)/σ and read Φ(z).
Distribution of the total
μT = 160 g, σT = 1.2·√4 = 2.4 g
Standardise
z = (164.8 − 160)/2.4 = 2
Probability
P = 1 − Φ(2) = 0.02275
Answer
P = 0.02275
14.Normal distribution
Answer: x = 182.7 cm
Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.
z for the percentile
Φ(z) = 0.75 → z = 0.6745
Back to x
x = 178 + 0.6745·7 = 182.72 cm
Answer
x = 182.72 cm
15.Confidence intervals
Answer: E = 12.39
Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.
Critical value
df = n − 1 = 7, t = 1.895
Margin of error
E = 1.895·18.5/√8 = 12.39
Answer
E = 12.39
16.Confidence intervals
Answer: n = 374
Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.
Solve for n
n = (2.576·15/2)² = 373.3
Round up
A sample size is a whole number, and rounding down would make the margin too large.
n = 374
Answer
n = 374
17.Hypothesis tests & confidence intervals
Answer: t = −1.801
Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).
Standard error of the mean difference
SE = 8.3/√7 = 3.137
Test statistic
t = −5.65/3.137 = −1.801
Answer
t = −1.801
With df = 6, the two-sided 5% critical value is 2.447; |t| is smaller, so H₀ is not rejected.
18.Hypothesis tests & confidence intervals
Answer: n = 40
Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).
Solve for n
n = (1.96·8/2.5)² = 39.34
Round up
n = 40
Answer
n = 40
19.Linear regression & correlation
Answer: r = −0.9733
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Centred sums
Sxy = 294 − 15·106/5 = −24
Sxx = 55 − 15²/5 = 10
Syy = 2308 − 106²/5 = 60.8
Correlation coefficient
r = −24/√(10·60.8) = −0.9733
Answer
r = −0.9733
20.Linear regression & correlation
Answer: x = 3.084
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Means
x̄ = 42/6 = 7
ȳ = 185/6 = 30.83
Sums of squares and products
Sxx = Σ(x − x̄)² = 70
Sxy = Σ(x − x̄)(y − ȳ) = 283
Regression line
b = 283/70 = 4.043
a = 30.83 − 4.043·7 = 2.533
ŷ = 2.533 + 4.043·x
Solve for x
x = (15 − 2.533)/4.043 = 3.084
Answer
x = 3.084
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