A property is expected to earn net rent of €2 000 next year. The rent is expected to grow by 2% per year forever. The required return is 5% per year. Find the value PV of the property today.
C1 = €2 000g = 2%r = 5%
PV = €
2.Time value of moneyHard
You borrow €20 000 at 4.8% per year, compounded monthly, and repay €275 at the end of every month. How many months does it take until the loan is repaid (the last payment may be smaller)? Give the number of payments N.
P = €20 000A = €2754.8% / 12
N = payments
3.NPV & IRRMedium
A machine costs €50 000 today. It generates €12 000 at the end of each year for 5 years and can then be sold for €7 500. The cost of capital is 8%. Find the net present value NPV.
C0 = €50 000CF = €12 000S = €7 500n = 5r = 8%
NPV = €
4.NPV & IRRHard
A project costs €100 000 today. Its cash flow is €12 500 at the end of year 1 and grows by 4% per year until the last cash flow at the end of year 8. The cost of capital is 12%. Find the net present value NPV.
C0 = €100 000CF1 = €12 500g = 4%n = 8r = 12%
NPV = €
5.Bond pricing & yieldMedium
A bond with a face value of €1 000 pays a 4.5% annual coupon in two half-yearly payments and matures in 3 years. The yield to maturity is 6% per year. Find the price P of the bond.
F = €1 000coupon = 4.5%YTM = 6%n = 3
P = €
6.Bond pricing & yieldHard
A bond with a face value of €1 000 pays an annual coupon of 7% and matures in 5 years. The yield to maturity is 5.5%. Find the Macaulay duration D in years.
F = €1 000coupon = 7%n = 5YTM = 5.5%
D = years
7.CAPM & WACCMedium
A company has equity worth €5 000 000 and debt worth €3 000 000. Its WACC is 9.31%, its pre-tax cost of debt is 4% and the tax rate is 21%. Find the cost of equity re.
A company has 1 000 000 shares at €40.00 each and 40 000 bonds trading at €980 each. The pre-tax cost of debt is 7% and the tax rate is 20%. The share’s beta is 1.2, the risk-free rate 2% and the market return 8.5%. Find the WACC.
β = 1.2rf = 2%rm = 8.5%rd = 7%T = 20%
WACC = %
9.Descriptive statisticsMedium
Find the sample standard deviation s of the data: 48, 57, 58, 45, 31, 37, 49.
n = 7
s =
10.Descriptive statisticsHard
Exam scores are normally distributed with mean 170 and standard deviation 8. Find the z-score z of a score of 166.
μ = 170σ = 8x = 166
z =
11.ProbabilityMedium
For the distribution shown, find the standard deviation σ of X.
x: 1, 2, 3, 4, 5p(x): 0.2, 0.1, 0.2, 0.2, 0.3
σ =
12.ProbabilityHard
A test has 9 multiple-choice questions. A student who guesses gets each one right with probability 0.4, independently. What is the probability P of exactly 5 correct answers?
n = 9p = 0.4k = 5
P =
13.Normal distributionMedium
Drag z so that the shaded area between −z and z under the standard normal curve is 0.9500. Find z to two decimals.
A = 0.9500
z =
14.Normal distributionHard
Hole diameters D are normal with mean 25.02 mm and standard deviation 0.015 mm. Shaft diameters d are independent and normal with mean 25 mm and standard deviation 0.01 mm. A randomly chosen shaft fits when D − d > 0. Find the probability P that it fits. Round z to two decimals.
hole: μ = 25.02 mm, σ = 0.015 mmshaft: μ = 25 mm, σ = 0.01 mm
P =
15.Confidence intervalsMedium
A sample of 11 items has mean 37 and standard deviation s = 19.5. The population is roughly normal. Find the margin of error E of a 99% confidence interval for the mean.
n = 11x̄ = 37s = 19.599%t(10) = 3.169
E =
16.Confidence intervalsHard
The population standard deviation is 27. How large a sample n do you need so that a 90% confidence interval for the mean has a margin of error of at most 4?
σ = 27E = 490%
n =
17.Hypothesis tests & confidence intervalsMedium
Two production lines make the same part. Line 1: a sample of 40 parts has mean length 95 mm, and the line's known standard deviation is 6 mm. Line 2: a sample of 100 parts has mean 97.1 mm, known standard deviation 9 mm. Find the test statistic z for H₀: μ₁ = μ₂, taking the difference as x̄₁ − x̄₂ (line 1 minus line 2).
How large must a sample be so that the 95% confidence interval for a mean has a margin of error of at most 2.5? The standard deviation is 4. Find the smallest sample size n.
σ = 4E = 2.595%
n =
19.Linear regression & correlationMedium
The table gives 5 paired observations of x = hours studied and y = exam score. Find Pearson's correlation coefficient r.
n = 5
r =
20.Linear regression & correlationHard
The table gives 6 paired observations of x = car age in years and y = price in k€. Use the least-squares line ŷ = a + b·x. Predict ŷ for x = 2.5.
n = 6x = 2.5
ŷ =
3Solutions
1.Time value of money
Answer: PV = 66667 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Rearrange the annuity formula
i = 0.004
(1 + i)−N = 1 − 20 000·0.004/275 = 0.7091
Solve with logarithms
N = −ln(0.7091)/ln(1.004) = 86.11
Round up to whole payments
86 full payments leave a small balance, which the last, smaller payment clears.
N = 87
Answer
N = 87 payments
3.NPV & IRR
Answer: NPV = 3017 €
Net present value: discount every cash flow back to today with the required rate of return r, then add them up: NPV = Σ CFₜ/(1 + r)ᵗ. A project with NPV > 0 earns more than r and adds value. The internal rate of return (IRR) is the rate at which NPV = 0.
Present value of the yearly cash flows
12 000·3.993 = 47 912.52
Present value of the salvage value
7 500/1.469 = 5 104.37
NPV
NPV = −50 000 + 47 912.52 + 5 104.37 = €3 016.89
Answer
NPV = €3 016.89
4.NPV & IRR
Answer: NPV = −30116 €
Net present value: discount every cash flow back to today with the required rate of return r, then add them up: NPV = Σ CFₜ/(1 + r)ᵗ. A project with NPV > 0 earns more than r and adds value. The internal rate of return (IRR) is the rate at which NPV = 0.
NPV is negative, so the project earns less than the required return.
5.Bond pricing & yield
Answer: P = 959.4 €
Bond pricing: a bond’s price is the present value of its cash flows, discounted at the yield to maturity (YTM): the coupons form an annuity and the face value is paid back at maturity. P = C·(1 − (1 + y)⁻ⁿ)/y + F/(1 + y)ⁿ. When the yield is above the coupon rate the bond trades below face value, and the other way round.
Per period
C = €22.50, i = 0.03, N = 6
Present value of the coupons
€22.50·(1 − 0.8375)/0.03 = €121.89
Present value of the face value
€1 000·0.8375 = €837.48
Price
P = €959.37
Answer
P = €959.37
The yield is above the coupon rate, so the bond sells at a discount.
6.Bond pricing & yield
Answer: D = 4.408 years
Duration: the Macaulay duration is the weighted average time at which a bond pays its cash flows, with the present values of the cash flows as weights: D = Σ t·PVₜ/P. The modified duration D/(1 + y) estimates the percentage price change for a small change in yield: %ΔP ≈ −Dmod·Δy.
Present value of each cash flow
t = 1: 70/1.055 = 66.35, t·PV = 66.35
t = 2: 70/1.113 = 62.89, t·PV = 125.78
t = 3: 70/1.174 = 59.61, t·PV = 178.84
t = 4: 70/1.239 = 56.51, t·PV = 226.02
t = 5: 1070/1.307 = 818.69, t·PV = 4 093.47
Duration
P = 1 064.05
D = 4 690.46/1 064.05 = 4.408
Answer
D = 4.408 years
7.CAPM & WACC
Answer: re = 13 %
Cost of capital: CAPM gives the return shareholders require: re = rf + β·(rm − rf). The weighted average cost of capital mixes equity and debt by their market values: WACC = E/V·re + D/V·rd·(1 − T), with V = E + D. Interest is tax-deductible, hence the (1 − T).
Weights
V = €8 000 000, E/V = 0.625, D/V = 0.375
Debt part of the WACC
0.375·4%·(1 − 0.21) = 1.185%
Cost of equity
re = (9.31% − 1.185%)/0.625 = 13%
Answer
re = 13%
8.CAPM & WACC
Answer: WACC = 7.721 %
Cost of capital: CAPM gives the return shareholders require: re = rf + β·(rm − rf). The weighted average cost of capital mixes equity and debt by their market values: WACC = E/V·re + D/V·rd·(1 − T), with V = E + D. Interest is tax-deductible, hence the (1 − T).
Market values
E = 1 000 000·€40.00 = €40 000 000
D = 40 000·€980 = €39 200 000
Cost of equity (CAPM)
re = 2% + 1.2·6.5% = 9.8%
Weights
V = €79 200 000, E/V = 0.5051, D/V = 0.4949
WACC
WACC = 0.5051·9.8% + 0.4949·7%·(1 − 0.2) = 7.721%
Answer
WACC = 7.721%
9.Descriptive statistics
Answer: s = 9.863
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Standardise
z = (166 − 170)/8 = −0.5
Answer
z = −0.5
11.Probability
Answer: σ = 1.487
Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.
Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.
From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.
Area to the left of z
Φ(z) = (1 + 0.9500)/2 = 0.9750
Read the z-table backwards
Find 0.9750 inside the table and read off z.
z = 1.96
Answer
z = 1.96
14.Normal distribution
Answer: P = 0.8665
Sums and differences of normal variables: if X and Y are independent and normal, X + Y and X − Y are normal too. Means add or subtract: E(X ± Y) = μX ± μY. Variances always add, also for a difference: Var(X ± Y) = σX² + σY², so σ = √(σX² + σY²). Standard deviations never add directly. The total of n independent items with the same distribution has mean n·μ and standard deviation σ·√n. Then standardise as usual: z = (x − mean)/σ and read Φ(z).
Distribution of the difference
μ = 25.02 − 25 = 0.02 mm, σ = 0.01803 mm
Standardise
z = (0 − 0.02)/0.01803 = −1.11
Probability
P = 1 − Φ(−1.11) = 0.8665
Answer
P = 0.8665
15.Confidence intervals
Answer: E = 18.63
Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.
Critical value
df = n − 1 = 10, t = 3.169
Margin of error
E = 3.169·19.5/√11 = 18.63
Answer
E = 18.63
16.Confidence intervals
Answer: n = 124
Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.
Solve for n
n = (1.645·27/4)² = 123.3
Round up
A sample size is a whole number, and rounding down would make the margin too large.
n = 124
Answer
n = 124
17.Hypothesis tests & confidence intervals
Answer: z = −1.606
Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.
Standard error of the difference
SE = √(6²/40 + 9²/100) = √1.71 = 1.308
Test statistic
z = (95 − 97.1)/1.308 = −1.606
Answer
z = −1.606
|z| < 1.96, so H₀ is not rejected at the 5% level (two-sided).
18.Hypothesis tests & confidence intervals
Answer: n = 10
Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).
Solve for n
n = (1.96·4/2.5)² = 9.834
Round up
n = 10
Answer
n = 10
19.Linear regression & correlation
Answer: r = 0.9894
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Means
x̄ = 35/5 = 7
ȳ = 428/5 = 85.6
Sums of squares and products
Sxx = Σ(x − x̄)² = 40
Sxy = Σ(x − x̄)(y − ȳ) = 178
Syy = Σ(y − ȳ)² = 809.2
Correlation coefficient
r = 178/√(40·809.2) = 0.9894
Answer
r = 0.9894
20.Linear regression & correlation
Answer: ŷ = 21
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Means
x̄ = 21/6 = 3.5
ȳ = 109/6 = 18.17
Sums of squares and products
Sxx = Σ(x − x̄)² = 17.5
Sxy = Σ(x − x̄)(y − ȳ) = −49.5
Regression line
b = −49.5/17.5 = −2.829
a = 18.17 − (−2.829)·3.5 = 28.07
ŷ = 28.07 − 2.829·x
Prediction
ŷ = 28.07 + (−2.829)·2.5 = 21
Answer
ŷ = 21
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