You need €10 000 in 9 years. An account pays 4.8% per year, compounded monthly. How much must you deposit today? Find the present value PV.
FV = €10 0004.8% / 12n = 9
PV = €
2.Time value of moneyHard
You save €500 at the end of every month for 17 years. The account pays 3% per year, compounded monthly. How much have you saved at the end? Find FV.
A = €5003% / 12N = 204
FV = €
3.NPV & IRRMedium
A project costs €250 000 today. It generates €26 000 at the end of the first year, and the cash flow then grows by 1% per year forever. The cost of capital is 9%. Find the net present value NPV.
C0 = €250 000CF1 = €26 000g = 1%r = 9%
NPV = €
4.NPV & IRRHard
A project costs €40 000 and returns €19 000, €21 000, €19 000 at the end of years 1 to 3. Cash flows can be reinvested at the cost of capital of 10%. Find the modified internal rate of return MIRR in percent.
You buy a bond with 6 years to maturity (face value €1 000, annual coupon 3%) when its yield to maturity is 4%. One year later, just after receiving the first coupon, you sell it when the yield to maturity is 4.5%. Find your holding period return HPR in percent.
F = €1 000coupon = 3%n = 6y0 = 4%y1 = 4.5%
HPR = %
6.Bond pricing & yieldHard
A bond with 11 years to maturity (face value €1 000, annual coupon 7%) sells for €1 166. The issuer can call it in 5 years at a call price of €1 070. Find the yield to call YTC in percent.
F = €1 000coupon = 7%P = €1 166call price = €1 070call in 5 years
YTC = %
7.CAPM & WACCMedium
A company has equity worth €5 000 000 and debt worth €1 000 000. Its WACC is 11.5%, its pre-tax cost of debt is 5% and the tax rate is 20%. Find the cost of equity re.
A company's shares have a beta of 1.5 at its current debt-to-equity ratio of 0.5. It plans to raise its debt-to-equity ratio to 1.5. The tax rate is 21%, the risk-free rate 1.5% and the market risk premium 5%. Find the cost of equity re after the change.
Find the sample standard deviation s of the data: 16, 14, 20, 12, 57.
n = 5
s =
10.Descriptive statisticsHard
Exam scores are normally distributed with mean 170 and standard deviation 12. Find the z-score z of a score of 158.
μ = 170σ = 12x = 158
z =
11.ProbabilityMedium
In how many ways N can a committee of 5 people be chosen from a group of 12? The order does not matter.
n = 12k = 5
N =
12.ProbabilityHard
A test has 9 multiple-choice questions. A student who guesses gets each one right with probability 0.5, independently. What is the probability P of exactly 2 correct answers?
n = 9p = 0.5k = 2
P =
13.Normal distributionMedium
Drag z so that the shaded area between −z and z under the standard normal curve is 0.4448. Find z to two decimals.
A = 0.4448
z =
14.Normal distributionHard
The heights of adult men are normally distributed with mean 178 cm and standard deviation 7 cm. Drag the cut-off so the shaded bottom 95% is to the left of it. Find the cut-off x.
μ = 178 cmσ = 7 cm95%
x = cm
15.Confidence intervalsMedium
The blood pressure of 7 patients is measured before and after a treatment. The differences d = before − after (mmHg) have mean 2.3 and standard deviation 7.2. Find the upper limit of the 99% confidence interval for the mean difference.
n = 7d̄ = 2.3sd = 7.299%t(6) = 3.707
upper limit = mmHg
16.Confidence intervalsHard
The population standard deviation is 25. How large a sample n do you need so that a 99% confidence interval for the mean has a margin of error of at most 4?
σ = 25E = 499%
n =
17.Hypothesis tests & confidence intervalsMedium
Two production lines make the same part. Line 1: a sample of 40 parts has mean length 131.5 mm, and the line's known standard deviation is 8 mm. Line 2: a sample of 40 parts has mean 134.3 mm, known standard deviation 3 mm. Find the test statistic z for H₀: μ₁ = μ₂, taking the difference as x̄₁ − x̄₂ (line 1 minus line 2).
A one-sided z test at α = 0.05 must detect a shift of the mean of 5 units with a power of 80%. The standard deviation is 17. Find the minimum sample size n.
The table gives 6 paired observations of x = car age in years and y = price in k€. Find the coefficient of determination r² of the least-squares line.
n = 6
r² =
20.Linear regression & correlationHard
The table gives 6 paired observations of x = temperature in °C and y = ice creams sold. Use the least-squares line ŷ = a + b·x. A new observation (24.5, 73) is made. Find its residual e = y − ŷ.
n = 6(24.5, 73)
e =
3Solutions
1.Time value of money
Answer: PV = 6498 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
Rate and number of periods
i = 0.048/12 = 0.004
N = 12·9 = 108
Present value
PV = FV/(1 + i)N = 10 000/1.539 = €6 497.69
Answer
PV = €6 497.69
2.Time value of money
Answer: FV = 132846 €
Time value of money: money today is worth more than the same amount later, because it can earn interest. With interest rate i per period, an amount grows as FV = PV·(1 + i)n. A series of equal payments (an annuity) is valued by adding up each payment, which gives the annuity formulas.
You paid in €102 000 yourself; the rest is interest.
3.NPV & IRR
Answer: NPV = 75000 €
Net present value: discount every cash flow back to today with the required rate of return r, then add them up: NPV = Σ CFₜ/(1 + r)ᵗ. A project with NPV > 0 earns more than r and adds value. The internal rate of return (IRR) is the rate at which NPV = 0.
Value of the cash flows
PV = 26 000/(0.09 − 0.01) = 325 000.00
NPV
NPV = 325 000.00 − 250 000 = €75 000.00
Answer
NPV = €75 000.00
NPV is positive, so the project earns more than the required return.
4.NPV & IRR
Answer: MIRR = 17.62 %
Modified IRR: compound every inflow forward to the end of the project at the reinvestment rate (usually the cost of capital) to get the terminal value TV. MIRR is the rate that turns the initial investment into TV: MIRR = (TV/C₀)^(1/n) − 1.
Terminal value of the inflows
19 000·1.12 = 22 990.00
21 000·1.11 = 23 100.00
19 000·1.10 = 19 000.00
TV = 65 090.00
MIRR
MIRR = (65 090.00/40 000)1/3 − 1 = 17.62%
Answer
MIRR = 17.62%
5.Bond pricing & yield
Answer: HPR = 1.749 %
Bond pricing: a bond’s price is the present value of its cash flows, discounted at the yield to maturity (YTM): the coupons form an annuity and the face value is paid back at maturity. P = C·(1 − (1 + y)⁻ⁿ)/y + F/(1 + y)ⁿ. When the yield is above the coupon rate the bond trades below face value, and the other way round.
Bond pricing: a bond’s price is the present value of its cash flows, discounted at the yield to maturity (YTM): the coupons form an annuity and the face value is paid back at maturity. P = C·(1 − (1 + y)⁻ⁿ)/y + F/(1 + y)ⁿ. When the yield is above the coupon rate the bond trades below face value, and the other way round.
Equation for the yield
1166 = 70·(1 − (1 + y)−5)/y + 1070/(1 + y)5
Solve numerically
y = 4%: €1 191.09
y = 5%: €1 141.44
YTC = 4.498%
Answer
YTC = 4.498%
The yield to maturity is 5.001%. Investors in a premium bond expect it to be called, so the lower yield to call is the more realistic one.
7.CAPM & WACC
Answer: re = 13 %
Cost of capital: CAPM gives the return shareholders require: re = rf + β·(rm − rf). The weighted average cost of capital mixes equity and debt by their market values: WACC = E/V·re + D/V·rd·(1 − T), with V = E + D. Interest is tax-deductible, hence the (1 − T).
Weights
V = €6 000 000, E/V = 0.8333, D/V = 0.1667
Debt part of the WACC
0.1667·5%·(1 − 0.2) = 0.6667%
Cost of equity
re = (11.5% − 0.6667%)/0.8333 = 13%
Answer
re = 13%
8.CAPM & WACC
Answer: re = 13.25 %
Levered beta (Hamada): debt makes equity riskier. βL = βU·(1 + (1 − T)·D/E), where βU is the beta of the business without debt. To move a beta to another capital structure, unlever it first and then relever it at the new D/E.
Unlever the beta
βU = 1.5/(1 + 0.79·0.5) = 1.075
Relever at the new D/E
βL = 1.075·(1 + 0.79·1.5) = 2.349
Cost of equity (CAPM)
re = 1.5% + 2.349·5% = 13.25%
Answer
re = 13.25%
9.Descriptive statistics
Answer: s = 18.79
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.
Standardise
z = (158 − 170)/12 = −1
Answer
z = −1
11.Probability
Answer: N = 792
Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.
Combinations
C(12, 5) = (12·11·10·9·8)/(5·4·3·2·1) = 792
Answer
N = 792
12.Probability
Answer: P = 0.07031
Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.
From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.
Area to the left of z
Φ(z) = (1 + 0.4448)/2 = 0.7224
Read the z-table backwards
Find 0.7224 inside the table and read off z.
z = 0.59
Answer
z = 0.59
14.Normal distribution
Answer: x = 189.5 cm
From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.
Area to the left
Φ(z) = 0.95
z from the table
z ≈ 1.64
Back to the original units
x = 178 + 1.64·7 = 189.5 cm
Answer
x = 189.5 cm
15.Confidence intervals
Answer: upper limit = 12.39 mmHg
Interval for a difference: estimate ± critical value × standard error. For two independent means with known σ: SE = √(σ₁²/n₁ + σ₂²/n₂) and z. With equal unknown variances: pooled s_p and t with n₁ + n₂ − 2 degrees of freedom. For paired data, work with the differences: d̄ ± t·s_d/√n.
Critical value
df = 6, t = 3.707
Margin of error
E = 3.707·7.2/√7 = 10.09
Interval
2.3 ± 10.09 → [−7.788, 12.39]
Answer
upper limit = 12.39 mmHg
16.Confidence intervals
Answer: n = 260
Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.
Solve for n
n = (2.576·25/4)² = 259.2
Round up
A sample size is a whole number, and rounding down would make the margin too large.
n = 260
Answer
n = 260
17.Hypothesis tests & confidence intervals
Answer: z = −2.073
Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.
Standard error of the difference
SE = √(8²/40 + 3²/40) = √1.825 = 1.351
Test statistic
z = (131.5 − 134.3)/1.351 = −2.073
Answer
z = −2.073
|z| > 1.96, so H₀ is rejected at the 5% level (two-sided).
18.Hypothesis tests & confidence intervals
Answer: n = 72
Sample size for a test: to detect a true shift δ with power 1 − β in a one-sided z test at level α, the standard error must satisfy δ = (z_α + z_β)·σ/√n, so n = ((z_α + z_β)·σ/δ)², rounded up.
Solve for n
n = ((1.645 + 0.842)·17/5)² = 71.5
Round up
n = 72
Answer
n = 72
19.Linear regression & correlation
Answer: r² = 0.91
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Means
x̄ = 21/6 = 3.5
ȳ = 125/6 = 20.83
Sums of squares and products
Sxx = Σ(x − x̄)² = 17.5
Sxy = Σ(x − x̄)(y − ȳ) = −25.5
Syy = Σ(y − ȳ)² = 40.83
Coefficient of determination
r² = −25.5²/(17.5·40.83) = 0.91
Answer
r² = 0.91
About 91% of the variation in y is explained by the line.
20.Linear regression & correlation
Answer: e = 2.167
Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.
Means
x̄ = 147/6 = 24.5
ȳ = 425/6 = 70.83
Sums of squares and products
Sxx = Σ(x − x̄)² = 157.5
Sxy = Σ(x − x̄)(y − ȳ) = 502.5
Regression line
b = 502.5/157.5 = 3.19
a = 70.83 − 3.19·24.5 = −7.333
ŷ = −7.333 + 3.19·x
Predicted value
ŷ = −7.333 + 3.19·24.5 = 70.83
Residual
e = 73 − 70.83 = 2.167
Answer
e = 2.167
The point lies above the line.
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