Computer Networks: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

IPv4 subnetting

Hosts per subnet
2(32 − prefix) − 2 (/31: 2, /32: 1)
Block size
256 − (mask octet)
Network address
IP AND mask
Broadcast address
IP OR (NOT mask): all host bits set to 1
Subnets from n borrowed bits
2n

Number systems

Place values
binary 2k, octal 8k, hex 16k
To decimal
Σ dk·bk
From decimal
divide by the base, read the remainders bottom-up
Hex ↔ binary
one hex digit = 4 bits
Two’s complement
invert the bits and add 1

2Practice problems

1.IPv4 subnettingMedium
255.255.255.25211111111111111111111111111111100network bitshost bits

A subnet uses the mask 255.255.255.252. How many usable host addresses H does it have?

255.255.255.252
H =
2.IPv4 subnettingHard
last octet = 100012816413201608140201networkhost

A host has the address 10.20.185.100/26. What is the fourth octet x of the last usable host address in its subnet?

10.20.185.100/26
x =
3.Computer networksMedium

What does an MX record in DNS specify?

  1. AThe mail servers that accept email for a domain
  2. BThe name servers for a zone
  3. CAn alias name for another host
  4. DThe IPv4 address of a web server
4.Computer networksHard

Which of these addresses is a public (not RFC 1918 private) IPv4 address?

  1. A192.168.255.1
  2. B172.31.0.1
  3. C10.255.0.1
  4. D172.32.0.1
5.Number systemsMedium
8-bit two's complement?−128?64?32?16?8?4?2?1

Write −12 as an 8-bit two's complement pattern. Read the pattern as an unsigned binary number: what is its value U in decimal?

N = −128 bit
U =
6.Number systemsHard
32-bit two's complement, N = ??sign???????????????????????????????

What is the most negative integer N that can be stored in 32-bit two's complement?

32 bit
N =

3Solutions

1.IPv4 subnetting

Answer: H = 2

IPv4 subnetting: an address has 32 bits. The prefix /p says how many leading bits identify the network; the remaining 32 − p bits number the hosts. A subnet has 2³²⁻ᵖ addresses, but the first (network address) and last (broadcast address) cannot be given to hosts, so 2³²⁻ᵖ − 2 hosts fit. Exceptions: a /31 (point-to-point link, RFC 3021) uses both of its 2 addresses for hosts, and a /32 is one single address (a single host or a loopback).

Prefix length

255.255.255.252 = /30

Usable hosts

22 − 2 = 2

Answer

H = 2
2.IPv4 subnetting

Answer: x = 126

IPv4 subnetting: an address has 32 bits. The prefix /p says how many leading bits identify the network; the remaining 32 − p bits number the hosts. A subnet has 2³²⁻ᵖ addresses, but the first (network address) and last (broadcast address) cannot be given to hosts, so 2³²⁻ᵖ − 2 hosts fit. Exceptions: a /31 (point-to-point link, RFC 3021) uses both of its 2 addresses for hosts, and a /32 is one single address (a single host or a loopback).

Block size

26 = 64

Subnet of this host

network: ⌊100/64⌋·64 = 64
broadcast: 64 + 64 − 1 = 127
usable hosts: 65 … 126

Answer

x = 126
3.Computer networks

Answer: A · The mail servers that accept email for a domain

Why this is the answer

MX (mail exchange) records list mail servers with priorities, so sending servers know where to deliver mail for that domain.

Answer

A · The mail servers that accept email for a domain
4.Computer networks

Answer: D · 172.32.0.1

Why this is the answer

172.16.0.0/12 runs from 172.16.0.0 to 172.31.255.255, so 172.32.0.1 lies outside it. The other three are in private ranges.

Answer

D · 172.32.0.1
5.Number systems

Answer: U = 244

Positional number systems: each digit is worth its value times a power of the base. In binary the places are worth 1, 2, 4, 8, 16, …; in hexadecimal 1, 16, 256, …, with A–F standing for 10–15. In 8-bit two's complement the leftmost bit is worth −128 instead of +128, which is how negative numbers are stored.

Invert and add one

12 = 0000 1100
inverted: 1111 0011
+1 → 1111 0100

Read it as unsigned

1111 0100₂ = 256 − 12 = 244

Answer

U = 244
6.Number systems

Answer: N = −2.147 × 10⁹

Positional number systems: each digit is worth its value times a power of the base. In binary the places are worth 1, 2, 4, 8, 16, …; in hexadecimal 1, 16, 256, …, with A–F standing for 10–15. In 8-bit two's complement the leftmost bit is worth −128 instead of +128, which is how negative numbers are stored.

Most negative value

−231 = −2147483648

Answer

N = −2147483648

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