Read the pH: below 7.35 is acidosis, above 7.45 alkalosis.
Find the value that explains it: PaCO₂ moving opposite to the pH is respiratory, HCO₃⁻ moving with the pH is metabolic.
Look at the other value: normal means uncompensated, abnormal in the compensating direction means partial compensation, and a normal pH with both abnormal means full compensation.
In a metabolic acidosis, compare PaCO₂ with Winter’s formula, 1.5·HCO₃⁻ + 8 ± 2, and calculate the anion gap Na⁺ − (Cl⁻ + HCO₃⁻).
Check a high anion gap with the delta ratio and, when albumin is low, with the corrected gap.
ECG rhythm strip interpretation
Paper (25 mm/s, 10 mm/mV)
1 small box = 0.04 s, 1 large box = 0.20 s, 10 mm = 1 mV
Heart rate, regular rhythm
300 ÷ large boxes = 1500 ÷ small boxes = 60 ÷ RR (s)
Heart rate, irregular rhythm
QRS complexes in 6 s × 10
Normal PR interval
0.12–0.20 s
Normal QRS duration
< 0.12 s
QTc (Bazett)
QT/√RR
QTc (Fridericia)
QT/∛RR
QTc (Framingham)
QT + 154·(1 − RR)
Sinus rates
bradycardia < 60, normal 60–100, tachycardia > 100 /min
Escape rates
junctional 40–60, ventricular 20–40 /min
Fast rhythms
SVT 150–250 /min (narrow), VT > 100 /min (wide)
Method
Rate: for a regular rhythm divide 300 by the large boxes or 1500 by the small boxes between two R waves; for an irregular rhythm count the QRS complexes in 6 seconds and multiply by 10.
Rhythm: compare the R–R intervals. Equal is regular; a repeating pattern is regularly irregular; no pattern at all is irregularly irregular.
P waves: is there an upright P wave in lead II before every QRS, all alike? Look for fibrillatory or sawtooth waves, inverted P waves and P waves without a QRS.
PR interval: from the start of P to the start of the QRS, normally 0.12–0.20 s and constant. Watch whether it lengthens, stays fixed before a dropped beat, or varies at random.
QRS duration: below 0.12 s is narrow; 0.12 s or more is wide. Then name the rhythm, and for the QT use QTc = QT/√RR (Bazett) with times in seconds.
Prioritization & delegation
Method
Ask what will harm the patient soonest if nothing is done.
Apply ABC (C-A-B in cardiac arrest), then Maslow: physiological needs before safety, safety before psychological needs.
Compare the options: acute before chronic, unstable before stable, unexpected before expected, systemic before local, and check each finding against the patient’s baseline.
Assess before you act unless it is an emergency; then choose the step the others depend on.
For delegation, check the five rights: task, circumstance, person, directions and supervision. Assessment, teaching and evaluation stay with the RN.
2Practice problems
1.Med-surg: cardiovascular & respiratoryMedium
A patient has a raised B-type natriuretic peptide (BNP or NT-proBNP). What does this mainly reflect?
ADamage to skeletal muscle after a fall
BIschaemic damage to the heart muscle
CInflammation of the liver from congestion
DStretch and pressure overload of the ventricles
2.Med-surg: cardiovascular & respiratoryHard
A nurse is planning care for four patients. Which patient should be assessed first?
AA patient with stable heart failure waiting for the daily weight
BA patient with a venous ulcer due for a dressing change
CA patient with controlled hypertension asking about salt
DA patient with COPD whose SpO₂ fell from 90% to 83% with new drowsiness
3.Med-surg: neuro, endocrine & renalMedium
Why is intermittent self-catheterisation often taught after a spinal cord injury?
AIt removes all risk of a urinary tract infection completely
BThe bladder may not empty, and regular emptying protects the kidneys
CIt is mainly used to measure the urine output accurately
DIt trains the bladder to grow gradually larger over time
4.Med-surg: neuro, endocrine & renalHard
A patient has frothy urine and marked leg swelling. Serum albumin is 18 g/L (1.8 g/dL), and BP is normal. The urine shows heavy protein but little blood. What is most likely?
AAcute pyelonephritis
BNephritic syndrome
CNephrotic syndrome
DA urethral stricture
5.Med-surg: GI, perioperative & oncologyMedium
Why might a patient's platelet count be monitored while they receive heparin?
ATo see whether the patient has an infection
BTo check whether the heparin is causing anaemia
CTo measure the heparin dose in the blood exactly
DTo detect heparin-induced thrombocytopenia
6.Med-surg: GI, perioperative & oncologyHard
Why is folinic acid (leucovorin) given after high-dose methotrexate?
ATo rescue normal cells from methotrexate toxicity
BTo treat the patient's anaemia only
CTo increase the anticancer effect on the tumour
DTo prevent hair loss during treatment
7.Clinical nursingMedium
Which of these is one of the "4 Hs", the reversible causes of cardiac arrest?
AHypoxia
BHyperthyroidism
CHypertension
DHyperventilation
8.Clinical nursingHard
During a general anaesthetic, a patient develops a rapidly rising temperature, muscle rigidity and rising carbon dioxide levels. What should be suspected?
AMalignant hyperthermia
BNeuroleptic malignant syndrome from antipsychotics
CPostoperative infection
DA normal response to surgery
9.Lab values & electrolytesMedium
A patient takes high-dose furosemide. Besides potassium, which electrolyte is most commonly lowered?
ASodium bicarbonate
BPhosphate
CUric acid
DMagnesium
10.Lab values & electrolytesHard
A patient has marked generalized edema. Results show heavy proteinuria, serum albumin 1.8 g/dL (18 g/L) and total cholesterol 340 mg/dL (8.8 mmol/L). Which condition fits best?
APrerenal kidney injury
BNephrotic syndrome
CLiver cirrhosis only
DAcute pyelonephritis
11.Arterial blood gas interpretationMedium
A practice arterial blood gas shows pH 7.14, PaCO₂ 43 mmHg (5.7 kPa) and HCO₃⁻ 14 mmol/L. The primary disorder is metabolic acidosis. How far is it compensated? Click your answer.
pH 7.14PaCO₂ 43 mmHg (5.7 kPa)HCO₃⁻ 14 mmol/L
1uncompensated
2partially compensated
3fully compensated
12.Arterial blood gas interpretationHard
Practice values: Na⁺ 136, Cl⁻ 106 and HCO₃⁻ 11 mmol/L. Calculate the delta ratio (AG − 12)/(24 − HCO₃⁻), using AG = Na⁺ − (Cl⁻ + HCO₃⁻). Give two decimals.
Na⁺ 136 mmol/LCl⁻ 106 mmol/LHCO₃⁻ 11 mmol/L
delta ratio =
13.ECG rhythm strip interpretationMedium
Measure the QT interval and the R–R interval on this regular lead II strip, then calculate the rate-corrected QTc with Bazett’s formula QTc = QT/√RR (both in seconds). Give the answer in seconds to three decimals.
lead II, 25 mm/s, 10 mm/mV1 small box = 0.04 s, 1 large box = 0.20 sstrip length 6 s
QTc = s
14.ECG rhythm strip interpretationHard
This lead II strip shows a conduction problem between the atria and the ventricles. Which rhythm is it? Click your answer.
lead II, 25 mm/s, 10 mm/mV1 small box = 0.04 s, 1 large box = 0.20 sstrip length 6 s
1second-degree AV block type I (Wenckebach)
2junctional rhythm
3first-degree AV block
4third-degree (complete) AV block
15.Prioritization & delegationMedium
Which task should the nurse delegate to a nursing assistant for a patient on fall precautions?
ADeciding whether the bed alarm is still needed
BAssessing and recording the patient’s fall risk score each morning
CTeaching the family how to prevent falls at home
DHelping the patient to the toilet every 2 hours as planned
16.Prioritization & delegationHard
Which patient is the best choice to move out of intensive care to make room for a new admission?
AOn a norepinephrine infusion whose dose was increased this morning
BAdmitted overnight with a GI bleed and still receiving blood
CExtubated 2 days ago, stable on 2 L/min nasal oxygen, no vasoactive infusions
DIntubated 1 hour ago for respiratory failure, still sedated
3Solutions
1.Med-surg: cardiovascular & respiratory
Answer: D · Stretch and pressure overload of the ventricles
Why this is the answer
Natriuretic peptides are released by ventricular myocytes in response to wall stretch. A normal level makes heart failure unlikely; a raised level supports the diagnosis and reflects severity. Levels can also be raised in renal failure and older age. Troponin, not BNP, reflects myocardial necrosis.
Answer
D · Stretch and pressure overload of the ventricles
2.Med-surg: cardiovascular & respiratory
Answer: D · A patient with COPD whose SpO₂ fell from 90% to 83% with new drowsiness
Why this is the answer
A falling saturation with new drowsiness suggests acute respiratory failure, possibly with hypercapnia, and needs immediate assessment. The other patients are stable and their needs can wait briefly.
Answer
D · A patient with COPD whose SpO₂ fell from 90% to 83% with new drowsiness
3.Med-surg: neuro, endocrine & renal
Answer: B · The bladder may not empty, and regular emptying protects the kidneys
Why this is the answer
Spinal cord injury often causes neurogenic bladder. Clean intermittent catheterisation at regular intervals empties the bladder, prevents high pressures, reduces infection and kidney damage and avoids triggering autonomic dysreflexia.
Answer
B · The bladder may not empty, and regular emptying protects the kidneys
4.Med-surg: neuro, endocrine & renal
Answer: C · Nephrotic syndrome
Why this is the answer
Heavy proteinuria, very low albumin and oedema point to nephrotic syndrome. Nephritic syndrome is mainly haematuria with hypertension and reduced urine output. The cause is investigated, often with a biopsy.
Answer
C · Nephrotic syndrome
5.Med-surg: GI, perioperative & oncology
Answer: D · To detect heparin-induced thrombocytopenia
Why this is the answer
Heparin-induced thrombocytopenia is an immune reaction, usually 5–10 days after starting heparin, that lowers platelets and paradoxically causes thrombosis. Monitoring depends on risk and local policy.
Answer
D · To detect heparin-induced thrombocytopenia
6.Med-surg: GI, perioperative & oncology
Answer: A · To rescue normal cells from methotrexate toxicity
Why this is the answer
Methotrexate inhibits dihydrofolate reductase. Timed folinic acid bypasses this block in normal cells, reducing toxicity such as mucositis and myelosuppression, while methotrexate levels and kidney function are monitored.
Answer
A · To rescue normal cells from methotrexate toxicity
7.Clinical nursing
Answer: A · Hypoxia
Why this is the answer
The 4 Hs are hypoxia, hypovolaemia, hypo- or hyperkalaemia and other metabolic causes, and hypothermia. The 4 Ts are thrombosis, tension pneumothorax, tamponade and toxins.
Answer
A · Hypoxia
8.Clinical nursing
Answer: A · Malignant hyperthermia
Why this is the answer
Malignant hyperthermia is a hypermetabolic reaction triggered by volatile anaesthetics or suxamethonium (succinylcholine) in susceptible people. It is treated urgently with dantrolene, cooling and stopping the trigger.
Answer
A · Malignant hyperthermia
9.Lab values & electrolytes
Answer: D · Magnesium
Why this is the answer
Loop diuretics block the Na-K-2Cl transporter in the loop of Henle, where much magnesium and calcium are also reabsorbed. They therefore commonly cause hypokalemia and hypomagnesemia, and they can raise uric acid and bicarbonate.Checked against:Magnesium Blood Test · MedlinePlus (NIH) (2023)
Answer
D · Magnesium
10.Lab values & electrolytes
Answer: B · Nephrotic syndrome
Why this is the answer
Nephrotic syndrome is heavy proteinuria with low albumin, edema and high lipids. Low albumin reduces oncotic pressure, causing edema, and the liver increases lipoprotein production. There is also a higher risk of clots and infection.Checked against:Nephrotic syndrome · MedlinePlus (NIH) (2025)
Answer
B · Nephrotic syndrome
11.Arterial blood gas interpretation
Answer: uncompensated
Reading a blood gas (ROME): first the pH: below 7.35 is acidaemia, above 7.45 alkalaemia. Then find the value that explains it. PaCO₂ (normal 35–45 mmHg, 4.7–6.0 kPa) is the respiratory part and moves Opposite to the pH in a respiratory disorder; HCO₃⁻ (normal 22–26 mmol/L) is the metabolic part and moves in the same direction as the pH (Respiratory Opposite, Metabolic Equal). The other value shows the compensation: normal means uncompensated; abnormal in the direction that pulls the pH back while the pH is still abnormal means partially compensated; a normal pH with both values abnormal means fully compensated. Ranges differ slightly between laboratories; these are practice values.
ROME, value by value
pH 7.14: acidaemia (below 7.35)
PaCO₂ 43 mmHg: normal (35–45)
HCO₃⁻ 14 mmol/L: low (22–26)
Compensation
Clinically, also check the expected compensation: Winter’s formula expects PaCO₂ 27–31 mmHg, so the measured 43 mmHg points to an additional respiratory acidosis (a mixed disorder). The answer above is the ROME exam classification.
uncompensated
Answer
uncompensated
12.Arterial blood gas interpretation
Answer: delta ratio = 0.5385
Expected compensation: in metabolic acidosis Winter’s formula predicts PaCO₂ = 1.5·HCO₃⁻ + 8 ± 2 mmHg; a measured value above that range points to an additional respiratory acidosis, below it to an additional respiratory alkalosis. The anion gap AG = Na⁺ − (Cl⁻ + HCO₃⁻), normally about 8–12 mmol/L, separates high-gap from normal-gap metabolic acidosis; low albumin hides a high gap (add 2.5 per g/dL that albumin is below 4.0). The delta ratio (AG − 12)/(24 − HCO₃⁻) between about 0.8 and 2 fits a pure high-gap acidosis (some texts use 1 instead of 0.8), below that an added normal-gap acidosis, and above 2 an added metabolic alkalosis.
Anion gap
AG = 136 − (106 + 11) = 19
Delta ratio
(19 − 12)/(24 − 11) = 7/13 = 0.5385
Answer
delta ratio = 0.5385
Below 1: an added normal anion gap acidosis.
13.ECG rhythm strip interpretation
Answer: QTc = 0.387 s
QT and QTc: the QT interval runs from the start of the QRS complex to the end of the T wave. It shortens as the heart rate rises, so it is corrected for rate with the R–R interval in seconds: Bazett QTc = QT/√RR and Fridericia QTc = QT/∛RR. Bazett is the formula most textbooks use; it over-corrects at fast rates, where Fridericia is preferred. Limits differ between references: a QTc above about 0.45 s in men or 0.46 s in women is usually called prolonged, and above 0.50 s markedly prolonged.
Measure
QT = 7.5 × 0.04 = 0.30 s
RR = 15 × 0.04 = 0.60 s
Bazett’s formula
QTc = 0.30/√0.60 = 0.30/0.7746 = 0.387 s
Answer
QTc = 0.387 s
Within the usual limits (about 0.45 s for men, 0.46 s for women). (387 ms)
14.ECG rhythm strip interpretation
Answer: third-degree (complete) AV block
AV blocks: march out the P waves and check which ones are followed by a QRS. First-degree: every P conducted, PR constant and above 0.20 s. Second-degree type I (Mobitz I, Wenckebach): the PR lengthens from beat to beat until one P wave is not conducted, then the cycle starts again (group beating). Second-degree type II (Mobitz II): the PR of the conducted beats stays constant, and P waves are suddenly not conducted; the QRS is often wide. Third-degree (complete) block: P waves and QRS complexes are each regular but independent, the PR varies at random and the atrial rate is faster than the escape rate (junctional 40–60/min with a narrow QRS, ventricular 20–40/min with a wide QRS). A 2:1 block cannot be called type I or type II from one strip.
Five steps
1. Rate: R–R = 55 small boxes, 1500 ÷ 55 ≈ 27 per minute.
2. Rhythm: R–R regular (2.20 s) and P–P regular (0.64 s), but the two are independent.
3. P waves: upright and regular at 94 per minute, but not linked to the QRS complexes; some hide in a QRS or a T wave.
4. PR interval: varies from beat to beat; there is no fixed relation.
5. QRS: 0.16 s, wide (0.12 s or more).
Interpretation
third-degree (complete) AV block
Answer
third-degree (complete) AV block
Type II and third-degree blocks are the ones that can suddenly progress, so textbooks rank them as more serious than type I.
15.Prioritization & delegation
Answer: D · Helping the patient to the toilet every 2 hours as planned
Why this is the answer
A scheduled toileting round is a routine task that follows the care plan. Scoring fall risk, deciding on interventions and teaching need nursing judgement.
Answer
D · Helping the patient to the toilet every 2 hours as planned
16.Prioritization & delegation
Answer: C · Extubated 2 days ago, stable on 2 L/min nasal oxygen, no vasoactive infusions
Why this is the answer
The extubated patient on low-flow oxygen with no vasoactive drugs is stable and improving. Recent intubation, rising vasopressor needs and an active bleed all need ICU-level care.
Answer
C · Extubated 2 days ago, stable on 2 L/min nasal oxygen, no vasoactive infusions