Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.Pharmacy calculationsMedium
A solution has a ratio strength of 1:1000. You need 0.58 mg. Draw up the volume in the 1 mL syringe: what volume V is that?
1:10000.58 mg
V = mL
2.Pharmacy calculationsHard
A vial holds 500 mg of powder. You add 1.7 mL of diluent, and the powder adds 0.8 mL of volume. The prescription is 240 mg. Draw up the dose: what volume V do you give?
500 mg1.7 mL + 0.8 mL240 mg
V = mL
3.Dosage calculationsMedium
A patient weighs 22 kg and is prescribed 25 mg/kg as a single dose. Find the dose D in mg.
22 kg25 mg/kg
D = mg
4.Dosage calculationsHard
You must prepare 200 mL of a 0.5% (w/v) solution from a 10% (w/v) stock solution. How much water W must be added to the stock?
C₁ = 10%C₂ = 0.5%V₂ = 200 mL
W = mL
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). A 96 kg patient is to receive an aminophylline infusion (salt factor S = 0.8: 80% of aminophylline is theophylline). The theophylline clearance is 0.05 L/kg/h. What aminophylline infusion rate R in mg/h gives a steady-state theophylline level of 15 mg/L?
96 kgCL = 0.05 L/kg/hCss = 15 mg/LS = 0.8
R = mg/h
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A 43-year-old woman weighs 84 kg and has a serum creatinine of 3.1 mg/dL (274 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual gentamicin regimen is 80 mg every 8 h for a creatinine clearance of 100 mL/min. Keeping the dose, the interval is lengthened in proportion to the fall in clearance. Find the new dosing interval τ. Round to one decimal place.
Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.
Strength in mg/mL
1000 mg/1000 mL = 1 mg/mL
Volume
V = 0.58/1 = 0.58 mL
Answer
V = 0.58 mL
2.Pharmacy calculations
Answer: V = 1.2 mL
Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.
Final volume and concentration
1.7 + 0.8 = 2.5 mL
C = 500/2.5 = 200 mg/mL
Volume
V = 240/200 = 1.2 mL
Answer
V = 1.2 mL
3.Dosage calculations
Answer: D = 550 mg
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Dose
25·22 = 550 mg
Answer
D = 550 mg
4.Dosage calculations
Answer: W = 190 mL
Solution strengths: a percentage strength is grams per 100 mL, so 1% = 1 g/100 mL = 10 mg/mL. A ratio strength 1:1000 means 1 g in 1000 mL = 1 mg/mL; 1:10 000 is 0.1 mg/mL. For a dilution the amount of drug stays the same: C₁·V₁ = C₂·V₂.
Volume of stock
V₁ = 0.5·200/10 = 10 mL
Water to add
W = 200 − 10 = 190 mL
Answer
W = 190 mL
5.Clinical pharmacokinetics
Answer: R = 90 mg/h
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Clearance
CL = 0.05·96 = 4.8 L/h
Infusion rate
R = CL·Css/S = 4.8·15/0.8 = 90 mg/h
Answer
R = 90 mg/h
6.Clinical pharmacokinetics
Answer: τ = 25.8 h
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Creatinine clearance (Cockcroft–Gault)
CrCl = (140 − 43)·84/(72·3.1)·0.85 = 31.03 mL/min
New interval
τ = 8·100/31.03 = 25.78 ≈ 25.8 h
Answer
τ = 25.8 h
In practice the interval is rounded to a convenient value such as 12, 24, 36 or 48 h.