Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.Pharmacy calculationsMedium
Practice exercise (made-up values, not clinical guidance). A vial contains cefuroxime 750 mg as a powder. The practice label says to add 7.2 mL of sterile water; the powder adds 0.3 mL to the volume. The prescribed dose is 300 mg. What volume V do you draw up? Round to one decimal place.
750 mg7.2 mL+0.3 mL300 mg
V = mL
2.Pharmacy calculationsHard
Practice exercise (made-up values, not clinical guidance). You have 50 g of 10% salicylic acid ointment. How many grams m of 2% salicylic acid ointment must you add to make a 4% ointment? Round to the nearest whole gram.
50 g · 10%2%4%
m = g
3.Dosage calculationsMedium
A dose of 15 mg is needed from a 0.5% (w/v) solution. What volume V contains this dose?
15 mg0.5% w/v
V = mL
4.Dosage calculationsHard
A patient is 163 cm tall and weighs 64 kg. The prescription is 135 mg/m². Using the Mosteller formula BSA = √(height (cm) × weight (kg)/3600), find the dose D in mg.
163 cm64 kg135 mg/m²
D = mg
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 9 mg/L at 1 h and 1.7 mg/L at 7 h. Assume first-order elimination. Find the elimination rate constant k.
C1 = 9 mg/L (1 h)C2 = 1.7 mg/L (7 h)
k = h⁻¹
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A 61 kg patient has a digoxin level of 0.4 mcg/L; the target is 0.8 mcg/L. The volume of distribution is 7 L/kg and the tablets have F = 0.7. What extra loading dose LD raises the level to the target?
61 kgVd = 7 L/kgC = 0.4 → 0.8 mcg/LF = 0.7
LD = mcg
3Solutions
1.Pharmacy calculations
Answer: V = 3 mL
Reconstitution: the powder takes up space, so the final volume is the diluent plus the powder volume. Concentration = drug in the vial/final volume, and the volume to give = dose/concentration. On a multi-strength label, use the concentration that belongs to the amount of diluent you actually added. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Final volume
7.2 + 0.3 = 7.5 mL
Concentration
750/7.5 = 100 mg/mL
Volume to give
V = 300/100 = 3 mL
Answer
V = 3 mL
2.Pharmacy calculations
Answer: m = 150 g
Alligation: to mix a higher strength H and a lower strength L into a target strength T, take (T − L) parts of H and (H − T) parts of L. The parts are crossed: each stock gets the distance from the target to the other stock. Water or a plain base counts as 0%. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Alligation parts
10%: 4 − 2 = 2 parts
2%: 10 − 4 = 6 parts
Scale to the amount you have
m = 50·6/2 = 150 g
Answer
m = 150 g
Check: 50 g + 150 g = 200 g of 4% ointment.
3.Dosage calculations
Answer: V = 3 mL
Solution strengths: a percentage strength is grams per 100 mL, so 1% = 1 g/100 mL = 10 mg/mL. A ratio strength 1:1000 means 1 g in 1000 mL = 1 mg/mL; 1:10 000 is 0.1 mg/mL. For a dilution the amount of drug stays the same: C₁·V₁ = C₂·V₂.
Concentration
0.5% = 5 mg/mL
Volume
V = 15/5 = 3 mL
Answer
V = 3 mL
4.Dosage calculations
Answer: D = 229.8 mg
Body-surface-area dosing: many cytotoxic and some paediatric doses are prescribed per square metre of body surface area: dose (mg) = dose per m² × BSA (m²). The Mosteller formula estimates BSA = √(height (cm) × weight (kg)/3600).
Body surface area
BSA = √(163·64/3600) = √2.898 = 1.702 m²
Dose
D = 135·1.702 = 229.8 mg
Answer
D = 229.8 mg
5.Clinical pharmacokinetics
Answer: k = 0.2778 h⁻¹
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Elimination rate constant
k = ln(9/1.7)/6 = 1.667/6 = 0.2778 h⁻¹
Answer
k = 0.2778 h⁻¹
6.Clinical pharmacokinetics
Answer: LD = 244 mcg
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Volume of distribution
Vd = 7·61 = 427 L
Rise needed
0.8 − 0.4 = 0.4 mcg/L
Loading dose
LD = 427·0.4/(1·0.7) = 244 mcg
Answer
LD = 244 mcg
In practice the dose is rounded to a convenient amount.