Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.Pharmacy calculationsMedium
A solution has a ratio strength of 1:1000. You need 0.38 mg. Draw up the volume in the 1 mL syringe: what volume V is that?
1:10000.38 mg
V = mL
2.Pharmacy calculationsHard
Practice exercise (made-up values, not clinical guidance). You must prepare 100 mL of 5% sodium chloride by mixing 23% and 3% sodium chloride. How many mL V of the 3% solution do you need? Round to the nearest whole mL.
23%3%5%100 mL
V = mL
3.Dosage calculationsMedium
A patient weighs 18 kg. The prescribed dose is 20 mg/kg per day, given in 3 equal doses. How many milligrams D are given per dose?
18 kg20 mg/kg/day3× per day
D = mg
4.Dosage calculationsHard
A patient is 119 cm tall and weighs 35 kg. The prescription is 175 mg/m². Using the Mosteller formula BSA = √(height (cm) × weight (kg)/3600), find the dose D in mg.
119 cm35 kg175 mg/m²
D = mg
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). After an IV dose of vancomycin, the level is 35 mg/L at 1 h and 13.9 mg/L at 17 h. Assume first-order elimination. Find the half-life t½.
C1 = 35 mg/L (1 h)C2 = 13.9 mg/L (17 h)
t½ = h
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A 67 kg patient on regular gentamicin doses is at steady state. The target is a peak of 8 mg/L and a trough of 1 mg/L, and the volume of distribution is 0.3 L/kg. Assuming rapid IV doses, what dose D raises the level from the trough to the peak?
67 kgVd = 0.3 L/kgCpeak = 8 mg/LCtrough = 1 mg/L
D = mg
3Solutions
1.Pharmacy calculations
Answer: V = 0.38 mL
Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.
Strength in mg/mL
1000 mg/1000 mL = 1 mg/mL
Volume
V = 0.38/1 = 0.38 mL
Answer
V = 0.38 mL
2.Pharmacy calculations
Answer: V = 90 mL
Alligation: to mix a higher strength H and a lower strength L into a target strength T, take (T − L) parts of H and (H − T) parts of L. The parts are crossed: each stock gets the distance from the target to the other stock. Water or a plain base counts as 0%. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Alligation parts
23%: 5 − 3 = 2 parts
3%: 23 − 5 = 18 parts
total: 20 parts
Share the volume
V = 100·18/20 = 90 mL
Answer
V = 90 mL
Check: 10 mL of 23% + 90 mL of 3% = 100 mL.
3.Dosage calculations
Answer: D = 120 mg
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Total per day
20·18 = 360 mg
Per dose
D = 360/3 = 120 mg
Answer
D = 120 mg
4.Dosage calculations
Answer: D = 188.2 mg
Body-surface-area dosing: many cytotoxic and some paediatric doses are prescribed per square metre of body surface area: dose (mg) = dose per m² × BSA (m²). The Mosteller formula estimates BSA = √(height (cm) × weight (kg)/3600).
Body surface area
BSA = √(119·35/3600) = √1.157 = 1.076 m²
Dose
D = 175·1.076 = 188.2 mg
Answer
D = 188.2 mg
5.Clinical pharmacokinetics
Answer: t½ = 12.01 h
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Elimination rate constant
k = ln(35/13.9)/16 = 0.9235/16 = 0.05772 h⁻¹
Half-life
t½ = 0.693/0.05772 = 12.01 h
Answer
t½ = 12.01 h
6.Clinical pharmacokinetics
Answer: D = 140.7 mg
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Volume of distribution
Vd = 0.3·67 = 20.1 L
Dose
D = 20.1·(8 − 1) = 140.7 mg
Answer
D = 140.7 mg
In practice the dose is rounded to a convenient amount.