Cari had L = limx→25 (√x − 5)/(x − 25).
Lembaran kerja Had dengan jawapan
1.Mudah
f(x) = (√x − 5)/(x − 25)x → 25
L =
2.Mudah
Cari had L = limx→−3 (x2 + 2x − 3)/(x + 3).
f(x) = (x2 + 2x − 3)/(x + 3)x → −3
L =
3.Sederhana
Cari had L = limx→∞ (√(x2 + 6x) − x).
f(x) = √(x2 + 6x) − xx → ∞
L =
4.Sederhana
Cari had L = limx→∞ (√(x2 − 6x) − x).
f(x) = √(x2 − 6x) − xx → ∞
L =
5.Sukar
Cari had L = limx→0 (e2x − 1 − 2x)/x².
f(x) = (e2x − 1 − 2x)/x²x → 0
L =
6.Sukar
Cari had L = limx→0 ln(1 + 4x)/sin(2x), dengan x dalam radian.
f(x) = ln(1 + 4x)/sin(2x)x → 0
L =
Kunci jawapan
- 1. L = 0.1
- 2. L = −4
- 3. L = 3
- 4. L = −3
- 5. L = 2
- 6. L = 2
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