Cari had L = limx→25 (√x − 5)/(x − 25).
Lembaran kerja Had dengan jawapan
1.Mudah
f(x) = (√x − 5)/(x − 25)x → 25
L =
2.Mudah
Cari had L = limx→1 (x3 − 1)/(x − 1).
f(x) = (x3 − 1)/(x − 1)x → 1
L =
3.Sederhana
Cari had L = limx→∞ (√(4x2 − 10x) − 2x).
f(x) = √(4x2 − 10x) − 2xx → ∞
L =
4.Sederhana
Cari had L = limx→∞ (√(x2 + 5x) − x).
f(x) = √(x2 + 5x) − xx → ∞
L =
5.Sukar
Cari had L = limx→0 (1 − cos 2x)/(2x²), dengan x dalam radian.
f(x) = (1 − cos 2x)/(2x²)x → 0
L =
6.Sukar
Cari had L = limx→0 ln(1 + 2x)/sin(4x), dengan x dalam radian.
f(x) = ln(1 + 2x)/sin(4x)x → 0
L =
Kunci jawapan
- 1. L = 0.1
- 2. L = 3
- 3. L = −2.5
- 4. L = 2.5
- 5. L = 1
- 6. L = 0.5
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