AC power & power factor worksheet with answers

Free printable AC power & power factor worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
P = ?QS = V·Iφ

A single-phase load draws 13 A (rms) from a 400 V (rms) supply at a power factor of 0.8 lagging. Find the real power P it takes.

V = 400 VI = 13 Apf = cos φ = 0.8
P = W
2.Easy
120 VloadP = 1872 W19.5 A

A voltmeter, an ammeter and a wattmeter connected to a single-phase inductive load read 120 V, 19.5 A and 1872 W. Find the power factor cos φ of the load.

V = 120 VI = 19.5 AP = 1872 W
cos φ =
3.Medium
400 V126 kW, 0.7526 kW, 1I

Two loads are connected in parallel to a 400 V single-phase supply: a 26 kW load at a power factor of 0.75 lagging and a 6 kW heater (unity power factor). Find the overall power factor cos φ seen by the supply.

V = 400 VP1 = 26 kW, pf1 = 0.75 laggingP2 = 6 kW, pf2 = 1
cos φ =
4.Medium
230 VR + jXP = 431 W2.5 A

An inductive load takes 2.5 A and 431 W from a 230 V (rms) single-phase supply. Model it as a resistance R in series with a reactance X. Find R.

V = 230 VI = 2.5 AP = 431 W
R = Ω
5.Hard
P1​ = 38 kWQ1​S1​φ

A 150 kVA single-phase transformer supplies a load of 38 kW at a power factor of 0.65 lagging. How much extra real power ΔP can be added as a resistive (unity power factor) load before the transformer reaches its kVA rating?

Smax = 150 kVAP1 = 38 kWpf1 = 0.65
ΔP = kW
6.Hard
P = 40 kWQ1​S1​φ1​QC​

A single-phase load takes 40 kW at a power factor of 0.75 lagging from a 400 V, 60 Hz supply. A capacitor connected in parallel raises the power factor to 0.9. Find the new line current Inew.

P = 40 kWpf1 = 0.75pf2 = 0.9V = 400 Vf = 60 Hz
Inew = A

Answer key

  1. 1. P = 4160 W
  2. 2. cos φ = 0.8
  3. 3. cos φ = 0.8129
  4. 4. R = 68.96 Ω
  5. 5. ΔP = 105.3 kW
  6. 6. Inew = 111.1 A

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