Arterial blood gas interpretation worksheet with answers

Free printable Arterial blood gas interpretation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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Name: ____________________   Date: ____________

1.Easy
pH7.357.457.22PaCO₂mmHg354540HCO₃⁻mmol/L222616respiratorymetabolicacidosisalkalosis

A practice arterial blood gas shows pH 7.22, PaCO₂ 40 mmHg (5.3 kPa) and HCO₃⁻ 16 mmol/L. Which primary disorder is it? Click the cell in the grid.

pH 7.22PaCO₂ 40 mmHg (5.3 kPa)HCO₃⁻ 16 mmol/L
  1. 1respiratory acidosis
  2. 2metabolic acidosis
  3. 3respiratory alkalosis
  4. 4metabolic alkalosis
2.Easy

A practice blood gas shows PaO₂ 100 mmHg (13.3 kPa) while the inspired oxygen is 35%. Calculate the ratio P/F = PaO₂/FiO₂ in mmHg.

PaO₂ 100 mmHg (13.3 kPa)FiO₂ 35%
P/F = mmHg
3.Medium
pH7.357.457.42PaCO₂mmHg354524HCO₃⁻mmol/L222615uncompensatedpartially compensatedfully compensated

A practice arterial blood gas shows pH 7.42, PaCO₂ 24 mmHg (3.2 kPa) and HCO₃⁻ 15 mmol/L. The primary disorder is respiratory alkalosis. How far is it compensated? Click your answer.

pH 7.42PaCO₂ 24 mmHg (3.2 kPa)HCO₃⁻ 15 mmol/L
  1. 1uncompensated
  2. 2partially compensated
  3. 3fully compensated
4.Medium
pH7.357.457.42PaCO₂mmHg354527HCO₃⁻mmol/L222617uncompensatedpartially compensatedfully compensated

A practice arterial blood gas shows pH 7.42, PaCO₂ 27 mmHg (3.6 kPa) and HCO₃⁻ 17 mmol/L. The primary disorder is respiratory alkalosis. How far is it compensated? Click your answer.

pH 7.42PaCO₂ 27 mmHg (3.6 kPa)HCO₃⁻ 17 mmol/L
  1. 1uncompensated
  2. 2partially compensated
  3. 3fully compensated
5.Hard

Practice values: Na⁺ 143, Cl⁻ 112, HCO₃⁻ 16 mmol/L and albumin 28 g/L. Find the albumin-corrected anion gap AGc = AG + 0.25·(40 − albumin).

Na⁺ 143 mmol/LCl⁻ 112 mmol/LHCO₃⁻ 16 mmol/Lalbumin 28 g/L
AGc = mmol/L
6.Hard

Practice values: Na⁺ 136, Cl⁻ 107, HCO₃⁻ 15 mmol/L and albumin 19 g/L. Find the albumin-corrected anion gap AGc = AG + 0.25·(40 − albumin).

Na⁺ 136 mmol/LCl⁻ 107 mmol/LHCO₃⁻ 15 mmol/Lalbumin 19 g/L
AGc = mmol/L

Answer key

  1. 1. metabolic acidosis
  2. 2. P/F = 285.7 mmHg
  3. 3. fully compensated
  4. 4. fully compensated
  5. 5. AGc = 18 mmol/L
  6. 6. AGc = 19.25 mmol/L

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