How much heat q is needed to warm 100 g of water from 27 °C to 55 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.
Calorimetry & enthalpy worksheet with answers
1.Easy
m = 100 gT1 = 27 °CT2 = 55 °Cc = 4.18 J/(g·°C)
q = kJ
2.Easy
31 kJ of heat is added to 500 g of water (c = 4.18 J/(g·°C)). Find the temperature rise ΔT.
q = 31 kJm = 500 gc = 4.18 J/(g·°C)
ΔT = °C
3.Medium
A 75 g block of copper (c = 0.385 J/(g·°C)) at 160 °C is dropped into 400 g of water (c = 4.18 J/(g·°C)) at 24 °C in an insulated cup. Find the final temperature Tf.
mmetal = 75 gcmetal = 0.385 J/(g·°C)Tmetal = 160 °Cmwater = 400 gTwater = 24 °Ccwater = 4.18 J/(g·°C)
Tf = °C
4.Medium
A 250 g block of zinc (c = 0.388 J/(g·°C)) at 120 °C is dropped into 200 g of water (c = 4.18 J/(g·°C)) at 23 °C in an insulated cup. Find the final temperature Tf.
mmetal = 250 gcmetal = 0.388 J/(g·°C)Tmetal = 120 °Cmwater = 200 gTwater = 23 °Ccwater = 4.18 J/(g·°C)
Tf = °C
5.Hard
Use the standard enthalpies of formation to find ΔH° for the reaction 2C4H10 + 13O₂ → 8CO₂ + 10H₂O(l).
ΔH°f(C4H10) = −125.6 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
ΔH° = kJ
6.Hard
Use the standard enthalpies of formation to find ΔH° for the reaction C6H12O6 + 6O₂ → 6CO₂ + 6H₂O(l).
ΔH°f(C6H12O6) = −1274 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
ΔH° = kJ
Answer key
- 1. q = 11.7 kJ
- 2. ΔT = 14.83 °C
- 3. Tf = 26.31 °C
- 4. Tf = 33.08 °C
- 5. ΔH° = −5755 kJ
- 6. ΔH° = −2802 kJ
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