Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
r = ?240 km/h

For passenger comfort the centripetal acceleration on a railway curve must not exceed 0.8 m/s². What is the smallest radius rmin for a curve taken at 240 km/h?

v = 240 km/hamax = 0.8 m/s²
rmin = m
2.Easy
r = ?240 km/h

For passenger comfort the centripetal acceleration on a railway curve must not exceed 2 m/s². What is the smallest radius rmin for a curve taken at 240 km/h?

v = 240 km/hamax = 2 m/s²
rmin = m
3.Medium
r = 85 mvmax​ = ?

A car drives over the top of a hump in the road, which is a circular arc of radius 85 m. Use g = 9.81 m/s². Above what speed vmax do the wheels leave the road at the top?

r = 85 mg = 9.81 m/s²
vmax = m/s
4.Medium
r = 115 mvmax​ = ?

A car takes a flat curve of radius 115 m. The coefficient of static friction between tyres and road is 0.7. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 115 mμs = 0.7g = 9.81 m/s²
vmax = m/s
5.Hard
r = 0.7 mv = 6.5 m/s

A 1.8 kg ball on a string 0.7 m long is swung in a vertical circle. At the lowest point it moves at 6.5 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 1.8 kgr = 0.7 mv = 6.5 m/sg = 9.81 m/s²
T = N
6.Hard
r = 0.6 mv = 9 m/s

A 1 kg ball on a string 0.6 m long is swung in a vertical circle. At the lowest point it moves at 9 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 1 kgr = 0.6 mv = 9 m/sg = 9.81 m/s²
T = N

Answer key

  1. 1. rmin = 5556 m
  2. 2. rmin = 2222 m
  3. 3. vmax = 28.88 m/s
  4. 4. vmax = 28.1 m/s
  5. 5. T = 126.3 N
  6. 6. T = 144.8 N

Full step-by-step solutions: practise this topic on examproblems.com.