Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 2 mvmax​ = ?

A 1.9 kg stone is whirled in a horizontal circle of radius 2 m on a smooth, level table, held by a string that breaks at a tension of 20 N. Find the highest speed vmax the stone can have.

m = 1.9 kgr = 2 mTmax = 20 N
vmax = m/s
2.Easy
r = 0.9 mv = ?300 rpm

A small object sits 90 cm from the axis of a disc that turns at a steady 300 revolutions per minute. Find the speed v of the object.

n = 300 rpmr = 0.9 m
v = m/s
3.Medium
r = 80 mvmax​ = ?

A car takes a flat curve of radius 80 m. The coefficient of static friction between tyres and road is 0.4. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 80 mμs = 0.4g = 9.81 m/s²
vmax = m/s
4.Medium
r = 80 mvmax​ = ?

A car takes a flat curve of radius 80 m. The coefficient of static friction between tyres and road is 0.3. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 80 mμs = 0.3g = 9.81 m/s²
vmax = m/s
5.Hard
r = 0.6 mv = 3.5 m/s

A 0.2 kg ball on a string 0.6 m long is swung in a vertical circle. At the lowest point it moves at 3.5 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 0.2 kgr = 0.6 mv = 3.5 m/sg = 9.81 m/s²
T = N
6.Hard
r = 1.2 mv = 8 m/s

A 0.5 kg ball on a string 1.2 m long is swung in a vertical circle. At the lowest point it moves at 8 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 0.5 kgr = 1.2 mv = 8 m/sg = 9.81 m/s²
T = N

Answer key

  1. 1. vmax = 4.588 m/s
  2. 2. v = 28.27 m/s
  3. 3. vmax = 17.72 m/s
  4. 4. vmax = 15.34 m/s
  5. 5. T = 6.045 N
  6. 6. T = 31.57 N

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