Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 200 m29 m/sac​ = ?

A 1500 kg car drives around a flat curve of radius 200 m at a constant 29 m/s. Find its centripetal acceleration ac.

m = 1500 kgv = 29 m/sr = 200 m
ac = m/s²
2.Easy
r = 0.75 mv = ?33 rpm

A small object sits 75 cm from the axis of a disc that turns at a steady 33 revolutions per minute. Find the speed v of the object.

n = 33 rpmr = 0.75 m
v = m/s
3.Medium
θ = 10°to centrev = ?

A curve of radius 80 m is banked at 10°. At what speed v can a car take it with no friction needed at all? Use g = 9.81 m/s².

r = 80 mθ = 10°g = 9.81 m/s²
v = m/s
4.Medium
r = 50 mvmax​ = ?

A car takes a flat curve of radius 50 m. The coefficient of static friction between tyres and road is 0.7. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 50 mμs = 0.7g = 9.81 m/s²
vmax = m/s
5.Hard
r = 0.6 m6.5 m/svtop​ = ?

A 1.7 kg ball on a light string 0.6 m long is swung in a vertical circle. At the lowest point its speed is 6.5 m/s. Ignore air resistance and use g = 9.81 m/s². Find the tension Ttop in the string at the highest point.

m = 1.7 kgr = 0.6 mvbottom = 6.5 m/sg = 9.81 m/s²
Ttop = N
6.Hard
R = 9 mh = 36 m

A 5 kg cart is released from rest at a height of 36 m on a frictionless track and runs through a vertical loop of radius 9 m. Use g = 9.81 m/s². Find the normal force Nbottom of the track on the cart at the bottom of the loop.

m = 5 kgh = 36 mR = 9 mg = 9.81 m/s²
Nbottom = N

Answer key

  1. 1. ac = 4.205 m/s²
  2. 2. v = 2.592 m/s
  3. 3. v = 11.76 m/s
  4. 4. vmax = 18.53 m/s
  5. 5. Ttop = 36.32 N
  6. 6. Nbottom = 441.5 N

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