1.Easy
A 1 kg stone is whirled in a horizontal circle of radius 0.9 m on a smooth, level table, held by a string that breaks at a tension of 100 N. Find the highest speed vmax the stone can have.
m = 1 kgr = 0.9 mTmax = 100 N
vmax = m/s
Circular motion worksheet with answers
2.Easy
A 0.6 kg stone is whirled in a horizontal circle of radius 0.3 m on a smooth, level table, held by a string that breaks at a tension of 30 N. Find the highest speed vmax the stone can have.
m = 0.6 kgr = 0.3 mTmax = 30 N
vmax = m/s
3.Medium
A car takes a flat curve of radius 80 m. The coefficient of static friction between tyres and road is 0.4. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.
r = 80 mμs = 0.4g = 9.81 m/s²
vmax = m/s
4.Medium
A car takes a flat curve of radius 85 m. The coefficient of static friction between tyres and road is 0.7. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.
r = 85 mμs = 0.7g = 9.81 m/s²
vmax = m/s
5.Hard
A 0.5 kg ball on a string 0.8 m long is swung in a vertical circle. At the lowest point it moves at 8.5 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.
m = 0.5 kgr = 0.8 mv = 8.5 m/sg = 9.81 m/s²
T = N
6.Hard
A curve of radius 140 m is banked at 25°, and the coefficient of static friction between tyres and road is 0.2. Use g = 9.81 m/s². Find the highest speed vmax at which a car can take the curve without sliding up and out.
r = 140 mθ = 25°μs = 0.2g = 9.81 m/s²
vmax = m/s
Answer key
- 1. vmax = 9.487 m/s
- 2. vmax = 3.873 m/s
- 3. vmax = 17.72 m/s
- 4. vmax = 24.16 m/s
- 5. T = 50.06 N
- 6. vmax = 31.77 m/s
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