Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
r = 110 m28 m/sF = ?

A 700 kg car drives around a flat curve of radius 110 m at a constant 28 m/s. Find the inward (centripetal) force Fc needed.

m = 700 kgv = 28 m/sr = 110 m
Fc = N
2.Easy
r = 190 m14 m/sF = ?

A 600 kg car drives around a flat curve of radius 190 m at a constant 14 m/s. Find the inward (centripetal) force Fc needed.

m = 600 kgv = 14 m/sr = 190 m
Fc = N
3.Medium
r = 60 mvmax​ = ?

A car takes a flat curve of radius 60 m. The coefficient of static friction between tyres and road is 0.5. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 60 mμs = 0.5g = 9.81 m/s²
vmax = m/s
4.Medium
L = 0.4 m60°

A small ball on a string of length 0.4 m moves in a horizontal circle so that the string makes a constant angle of 60° with the vertical (a conical pendulum). Use g = 9.81 m/s². Find the speed v of the ball.

L = 0.4 mθ = 60°g = 9.81 m/s²
v = m/s
5.Hard
θ = 15°to centrevmax​ = ?

A curve of radius 90 m is banked at 15°, and the coefficient of static friction between tyres and road is 0.2. Use g = 9.81 m/s². Find the highest speed vmax at which a car can take the curve without sliding up and out.

r = 90 mθ = 15°μs = 0.2g = 9.81 m/s²
vmax = m/s
6.Hard
r = 1.4 mv = 5.5 m/s

A 1.9 kg ball on a string 1.4 m long is swung in a vertical circle. At the lowest point it moves at 5.5 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 1.9 kgr = 1.4 mv = 5.5 m/sg = 9.81 m/s²
T = N

Answer key

  1. 1. Fc = 4989 N
  2. 2. Fc = 618.9 N
  3. 3. vmax = 17.16 m/s
  4. 4. v = 2.426 m/s
  5. 5. vmax = 20.89 m/s
  6. 6. T = 59.69 N

Full step-by-step solutions: practise this topic on examproblems.com.