Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%1.5f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives aminophylline as a constant IV infusion without a loading dose. The half-life is 9 h. What percentage f of the steady-state level has been reached after 13.5 h?

t½ = 9 ht = 13.5 h
f = %
2.Easy
t/t½C/Css (%)100%1.5f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives lidocaine as a constant IV infusion without a loading dose. The half-life is 1.5 h. What percentage f of the steady-state level has been reached after 2.25 h?

t½ = 1.5 ht = 2.25 h
f = %
3.Medium
VCss​ = 12 mg/LR = ? mg/hCL = 0.035 L/kg/h52 kg

Practice exercise (made-up values, not clinical guidance). A 52 kg patient receives a theophylline infusion. The clearance is 0.035 L/kg/h. What infusion rate R in mg/h gives a steady-state level of 12 mg/L?

52 kgCL = 0.035 L/kg/hCss = 12 mg/L
R = mg/h
4.Medium
110100t (h)C (mg/L)1 h10 mg/L7 h3 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 10 mg/L at 1 h and 3 mg/L at 7 h. Assume first-order elimination. Find the half-life t½.

C1 = 10 mg/L (1 h)C2 = 3 mg/L (7 h)
t½ = h
5.Hard
Vd = 0.3 L/kg1 → 8 mg/LD = ? mg99 kg

Practice exercise (made-up values, not clinical guidance). A 99 kg patient on regular tobramycin doses is at steady state. The target is a peak of 8 mg/L and a trough of 1 mg/L, and the volume of distribution is 0.3 L/kg. Assuming rapid IV doses, what dose D raises the level from the trough to the peak?

99 kgVd = 0.3 L/kgCpeak = 8 mg/LCtrough = 1 mg/L
D = mg
6.Hard
VCss,avg​ = 10 mg/LD = ? mg · q8hCL = 0.035 L/kg/h81 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). An 81 kg patient takes oral theophylline (F = 1) every 8 h. The clearance is 0.035 L/kg/h. What dose D in mg gives an average steady-state level of 10 mg/L?

CL = 0.035 L/kg/hτ = 8 hS = 1F = 181 kgCss,avg = 10 mg/L
D = mg

Answer key

  1. 1. f = 64.64 %
  2. 2. f = 64.64 %
  3. 3. R = 21.84 mg/h
  4. 4. t½ = 3.454 h
  5. 5. D = 207.9 mg
  6. 6. D = 226.8 mg

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