Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
Vd = 0.3 L/kgC = 6 mg/LLD = ?69 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 69 kg needs a loading dose of tobramycin to reach a level of 6 mg/L straight away. The volume of distribution is 0.3 L/kg. Find the loading dose LD in mg.

69 kgVd = 0.3 L/kgC = 6 mg/L
LD = mg
2.Easy
t/t½C/Css (%)100%2f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives lidocaine as a constant IV infusion without a loading dose. The half-life is 1.5 h. What percentage f of the steady-state level has been reached after 3 h?

t½ = 1.5 ht = 3 h
f = %
3.Medium
VCss​ = 2.5 mg/LR = ? mg/minCL = 500 mL/min

Practice exercise (made-up values, not clinical guidance). A patient has a lidocaine clearance of 500 mL/min. What infusion rate R in mg/min keeps the steady-state level at 2.5 mg/L?

CL = 500 mL/minCss = 2.5 mg/L
R = mg/min
4.Medium
0.1110t (h)C (mg/L)2 h6 mg/L10 h0.9 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 6 mg/L at 2 h and 0.9 mg/L at 10 h. Assume first-order elimination. Find the half-life t½.

C1 = 6 mg/L (2 h)C2 = 0.9 mg/L (10 h)
t½ = h
5.Hard
t (h)C (mg/L)Css​t = ?95%

Practice exercise (made-up values, not clinical guidance). A theophylline infusion is started without a loading dose. The half-life in this patient is 9 h. How long t does it take to reach 95% of the steady-state level?

t½ = 9 h95% Css
t = h
6.Hard
Vd = 7 L/kg0.5 → 1 mcg/LLD = ? mcg82 kg · S = 1 · F = 0.7

Practice exercise (made-up values, not clinical guidance). An 82 kg patient has a digoxin level of 0.5 mcg/L; the target is 1 mcg/L. The volume of distribution is 7 L/kg and the tablets have F = 0.7. What extra loading dose LD raises the level to the target?

82 kgVd = 7 L/kgC = 0.5 → 1 mcg/LF = 0.7
LD = mcg

Answer key

  1. 1. LD = 124.2 mg
  2. 2. f = 75 %
  3. 3. R = 1.25 mg/min
  4. 4. t½ = 2.923 h
  5. 5. t = 38.9 h
  6. 6. LD = 410 mcg

Full step-by-step solutions: practise this topic on examproblems.com.