Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)C (mg/L)35 mg/L23 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the vancomycin level is 35 mg/L. The half-life is 6 h, and the drug is eliminated by first-order kinetics. What is the level C 23 h later?

C₀ = 35 mg/Lt½ = 6 ht = 23 h
C = mg/L
2.Easy
110100t (h)CC₀t½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, gentamicin has an elimination half-life of 2.5 h. Find the elimination rate constant k in h⁻¹.

t½ = 2.5 h
k = h⁻¹
3.Medium
110100t (h)C (mg/L)C₀ = 10 mg/Lt½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 220 mg of tobramycin. The level back-extrapolated to time zero is 10 mg/L and the half-life is 2.5 h. Find the clearance CL in L/h.

D = 220 mgC₀ = 10 mg/Lt½ = 2.5 h
CL = L/h
4.Medium
110t (h)C (mg/L)1 h6 mg/L3 h3 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 6 mg/L at 1 h and 3 mg/L at 3 h. Assume first-order elimination. Find the elimination rate constant k.

C1 = 6 mg/L (1 h)C2 = 3 mg/L (3 h)
k = h⁻¹
5.Hard
Vd = 7 L/kg0.5 → 0.8 mcg/LLD = ? mcg56 kg · S = 1 · F = 0.7

Practice exercise (made-up values, not clinical guidance). A 56 kg patient has a digoxin level of 0.5 mcg/L; the target is 0.8 mcg/L. The volume of distribution is 7 L/kg and the tablets have F = 0.7. What extra loading dose LD raises the level to the target?

56 kgVd = 7 L/kgC = 0.5 → 0.8 mcg/LF = 0.7
LD = mcg
6.Hard
Vd = 7 L/kg0.4 → 1 mcg/LLD = ? mcg62 kg · S = 1 · F = 0.7

Practice exercise (made-up values, not clinical guidance). A 62 kg patient has a digoxin level of 0.4 mcg/L; the target is 1 mcg/L. The volume of distribution is 7 L/kg and the tablets have F = 0.7. What extra loading dose LD raises the level to the target?

62 kgVd = 7 L/kgC = 0.4 → 1 mcg/LF = 0.7
LD = mcg

Answer key

  1. 1. C = 2.455 mg/L
  2. 2. k = 0.2773 h⁻¹
  3. 3. CL = 6.1 L/h
  4. 4. k = 0.3466 h⁻¹
  5. 5. LD = 168 mcg
  6. 6. LD = 372 mcg

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