Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%597%

Practice exercise (made-up values, not clinical guidance). A patient starts regular doses of phenobarbital, which has a half-life of 80 h. Using the rule that steady state is reached after about five half-lives, after how many hours tss is steady state reached?

t½ = 80 h
tss = h
2.Easy
t/t½C/Css (%)100%597%

Practice exercise (made-up values, not clinical guidance). A patient starts regular doses of theophylline, which has a half-life of 9 h. Using the rule that steady state is reached after about five half-lives, after how many hours tss is steady state reached?

t½ = 9 h
tss = h
3.Medium
VCss​ = 15 mg/LR = ? mg/h · S = 0.8CL = 0.04 L/kg/h53 kg

Practice exercise (made-up values, not clinical guidance). A 53 kg patient is to receive an aminophylline infusion (salt factor S = 0.8: 80% of aminophylline is theophylline). The theophylline clearance is 0.04 L/kg/h. What aminophylline infusion rate R in mg/h gives a steady-state theophylline level of 15 mg/L?

53 kgCL = 0.04 L/kg/hCss = 15 mg/LS = 0.8
R = mg/h
4.Medium
Vd = 0.7 L/kgC = 20 mg/LLD = ? mg82 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). An 82 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 20 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.

82 kgVd = 0.7 L/kgC = 20 mg/LS = 0.92
LD = mg
5.Hard
Vd = 0.3 L/kg1 → 10 mg/LD = ? mg59 kg

Practice exercise (made-up values, not clinical guidance). A 59 kg patient on regular gentamicin doses is at steady state. The target is a peak of 10 mg/L and a trough of 1 mg/L, and the volume of distribution is 0.3 L/kg. Assuming rapid IV doses, what dose D raises the level from the trough to the peak?

59 kgVd = 0.3 L/kgCpeak = 10 mg/LCtrough = 1 mg/L
D = mg
6.Hard
VCss,avg​ = ?400 mg · q12hCL = 0.045 L/kg/h50 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A 50 kg patient takes oral theophylline (F = 1) every 12 h. The clearance is 0.045 L/kg/h. Each dose is 400 mg of theophylline. Find the average steady-state level Css,avg.

CL = 0.045 L/kg/hτ = 12 hS = 1F = 150 kgD = 400 mg
Css,avg = mg/L

Answer key

  1. 1. tss = 400 h
  2. 2. tss = 45 h
  3. 3. R = 39.75 mg/h
  4. 4. LD = 1248 mg
  5. 5. D = 159.3 mg
  6. 6. Css,avg = 14.81 mg/L

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